Answer:
To create function h, function f was translated 2 units right
, translated 4 units up and reflected across the x axis
Step-by-step explanation:
Given
Required
Complete chart
First: f(x) was translated right by 2 units
The rule of right translation is 
So, we have:
Next: f'(x) was translated up by 4 units
The rule of down translation is 
So, we have:
Lastly, f"(x) was reflected across the x-axis;
The rule of this reflection is: 
So, we have:
![h(x) = -[(x+2)^3 + 4]](https://tex.z-dn.net/?f=h%28x%29%20%3D%20-%5B%28x%2B2%29%5E3%20%2B%204%5D)
Remove bracket
The first one is 37 and the second one is 49
I'm going to assume that you meant the following:
(x-1)
---------------
x^2-3x+2
Factoring the denominator, we get:
(x-1)
------------
(x-1)(x-2)
Notice that we have x-1 in both the numerator and the denominator. This factor cancels. HOWEVER: x can still not equal 1, which would lead to div. by zero. With the factor x-1 cancelled, we have 1 / (x-2). As x approaches 1 from either side, y approaches 1 / (1-2), or 1 / (-1), or -1. Thus, the limit exists and is -1.
7q² - 28 = 0
+ 28 + 28
7q² = 28
7 7
q² = 4
q = ±4
q = 4 or q = -4
Solution Set: {±4} and {q|q = 4 or q = -4}
Answer:
fghffjfghxhhg
56
Step-by-step explanation:
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