Answer:
The answer to your question is the third histogram
Step-by-step explanation:
What we must check in a histogram is that the x-axis is represented the intervals and in the y-axis is represented the frequency.
The first histogram is incorrect just by observing the first bar, we notice that the correct frequency from 0 to 4 is 3, not 14. This histogram is incorrect.
Also, the second histogram is incorrect, the frequency of the first category is 3, not 12. This histogram is wrong.
The third histogram is correct because all the bars are in agreement with their frequencies.
The last histogram is incorrect, for example, the last frequency is 12, not 3.
6)
2(9+10) = 38
2(5+6) = 22
P = 38+22=60 in
14)
9 x 10 = 90
6 x 5 = 30
A = 90+50 = 140 in^2
Answer:
Ok
Step-by-step explanation:
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