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Scorpion4ik [409]

3 years ago

7

Samuel exercises everyday. She spends 40% of his exercise on the treadmill. If he uses the treadmill 40 minutes each day, how ma

ny minutes does he exercise each day?

1 answer:

padilas [110]3 years ago

3 0

Samuel exercises for 100 minutes each day. Or in other words, 1 hour and 40 minutes.

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Solve for x. Round to the nearest tenth.

kondor19780726 [428]

Answer:

22.8

Step-by-step explanation:

$a^{2} +b^{2} =c^{2} \\20^{2} +11^{2} =x^{2} \\400+121=x^{2}\\\sqrt{521} =x\\\\or\\\\22.8 = x$

5 0

3 years ago

In ∆GHI, the measure of I=90°, the measure of G=82°, and GH = 3.4 feet. Find the length of HI to the nearest tenth of a foot.

natka813 [3]

Answer: 3.4

Step-by-step explanation:

i got this problem on delta math

3 0

3 years ago

Find the slope of the line that passes through \left(10,8\right)(10,8) and \left(1,9\right)(1,9).

sdas [7]

Answer:

m = -1/9

Step-by-step explanation:

7 0

2 years ago

Geometric Series assistance

Levart [38]

we have been asked to find the sum of the series

$\sum _{n=1}^5\left(\frac{1}{3}\right)^{n-1}$

As we know that a geometric series has a constant ratio "r" and it is defined as

$r=\frac{a_{n+1}}{a_n}=\frac{\left(\frac{1}{3}\right)^{\left(n+1\right)-1}}{\left(\frac{1}{3}\right)^{n-1}}=\frac{1}{3}$

The first term of the series is $a_1=\left(\frac{1}{3}\right)^{1-1}=1$

Geometric series sum formula is

$S_n=a_1\frac{1-r^n}{1-r}$

Plugin the values we get

$S_5=1\cdot \frac{1-\left(\frac{1}{3}\right)^5}{1-\frac{1}{3}}$

On simplification we get

$S_5=\frac{121}{81}$

Hence the sum of the given series is $\frac{121}{81}$

5 0

3 years ago

10m^3 of air weigh 13 kg.

Lemur [1.5K]

49.686‬ kg

Step-by-step explanation:

Since the density of the air remains constant in the question

We can represent this equation as a ratio;

10 m³ = 13 kg

(4.2 * 3.5 * 2.6) m³ = ? (x) kg

4.2 * 3.5 * 2.6 = 38.22

We cross multiply

38.22 * 13 = 10 * x

X = 496.86‬ /10

X = 49.686‬

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3 0

3 years ago