A trig identity is <span>asinucosu=<span>a/2</span>sin(2u)</span>So you can write your equation as<span>y=sin(x)cos(x)=<span>1/2</span>sin(2x)</span>Use the crain rule here<span><span>y′</span>=<span>d/<span>dx</span></span><span>1/2</span>sin(2x)=<span>1/2</span>cos(2x)<span>d/<span>dx</span></span>2x=cos(2x)</span>The curve will have horizontal tangents when y' = 0.<span><span>y′</span>=0=cos(2x)</span>On the interval [-pi, pi], solution to that is<span><span>x=±<span>π4</span>,±<span><span>3π</span>4</span></span></span>
i mean ig but 129.... ehh
Answer:
(2, -3)
Step-by-step explanation:
Apparently, the equations are supposed to be ...
The solution for x can be found by subtracting the second equation from the first:
(4x +y) -(3x +y) = (5) -(3)
x = 2 . . . . . . . matches the second answer choice
Y can be found from either equation:
y = 5 - 4x . . . . . subtract 4x from the first equation
y = 5 -4(2) = -3
The solution is (x, y) = (2, -3).
Answer: imma figure this out
Step-by-step explanation:
Answer:
(5y+3) x (y-2)
Step-by-step explanation:
5y^2-7y-6
5y^2+3y-10y-6
y(5y+3(-2(5y+3)
(5y+3) x (y-2)
