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nignag [31]
3 years ago
6

Jamey traveled 45 miles in 15 minutes. Find his average speed per minute for this situation.

Mathematics
1 answer:
Ad libitum [116K]3 years ago
8 0

Answer:

3 miles per min

Step-by-step explanation:

3 miles x 15 (min) = 45 mph

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Find the values of c such that the area of the region bounded by the parabolas y = 16x2 − c2 and y = c2 − 16x2 is 144. (Enter yo
natita [175]
Y=16*2 -c*2
y=32-2c
y=-2c+32
c= - (y-32)/2
8 0
3 years ago
The expressions p(200-5p)and 200p-5p2define the same function. The function models the revenue a school would earn from selling
harkovskaia [24]

Answer:

When the price of a ticket = $0 or $40, there will be no revenue.

The revenue will be $500 if each ticket cost $37.3 or $2.68

Step-by-step explanation:

Let R(p) = p(200-5p)

when R(p) = 0

p(200-5p) = 0

p = 0 or 200-5p = 0

When the price of a ticket = $0 or $40, there will be no revenue.

when R(p) = 500

200p - 5p² = 500

5p² - 200p + 500 = 0

p = $37.3 or $2.68 (3 sig. fig.)

The required prices are $37.3 and $2.68

7 0
3 years ago
Read 2 more answers
√9 is __________ number *
Lera25 [3.4K]

Answer:

√9 is ____rational______ number *

Step-by-step explanation:

√9 = √(3×3)=3 which is rational

7 0
2 years ago
Suceción numerica 265 250 235 220 ____ ____ 175 ____ 145 130 ____ ____ ____ y aqui otra 4 12 36 ____ ____ ____ 2916 8748 ____ __
alina1380 [7]

Respuesta:

A la primera le vas a quitar 15 con cada número. A la segunda, todo lo multiplicas por 3 cada vez que vas avanzando.

265, 250 . . . 220, 205, 190, 175, 160, 145, 130, 115, 100, 185. ---------- 4, 12, 36, 108, 324, 972, 2,916, 8,748, 26,244, 78,732. ---------- 5, 20, 15, 40, 25, 60, 35, 80, 45, 90, 55, 100, 65, 110, 75. ---------- 30, 90, 270, 810, 2,430, 7,290, 21,870, 65,610, 196,830. ---------- 703125, 140625, 28125, 5625, 1125, 225, 45, 9. ---------- 36864, 9216, 2304, 576, 144, 36, 9, 2.25.

8 0
3 years ago
Karen runs a print shop that makes posters for large companies. It is a very competitive business. The market price is currently
kumpel [21]
AFC = FC / Quantity printed 

<span>So given she prints 1,000 posters: AFC = 250.00/1000 = $0.25 </span>
<span>Given she prints 2,000 posters: AFC = 250.00/2000 = $0.125 </span>
<span>Given she prints 10,000 posters: AFC = 250.00/2000 = $0.025 </span>

<span>ATC = TC / Quantity printed </span>

<span>where TC = FC + Variable C * Quantity printed </span>

<span>If she prints 1000: TC = 250 + 2000*1000 = 2,000,250 </span>
<span>ATC = 2,000,250/1000 = 2000.25 </span>

<span>If she prints 2000: TC = 250 + 1600*2000 = 3,200,250 </span>
<span>ATC = 3,200,250/2000 = 1600.125 </span>

<span>If she prints 10000: TC = 250 + 1600*2000 + 1000*8000 ($1000 for each additional poster after 2000) = 11,200,250 </span>
<span>ATC = 11,200,250/10000 = 1120.025</span>
7 0
3 years ago
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