Answer:
<h2>A. (0,1)</h2>
Step-by-step explanation:
The question lacks the e=required option. Find the complete question below with options.
Which of the following points does not belong to the quadratic function
f(x) = 1-x²?
a.(0,1) b.(1,0) c.(-1,0)
Let f(x) = 0
The equation becomes 1-x² = 0
Solving 1-x² = 0 for x;
subtract 1 from both sides;
1-x²-1 = 0-1
-x² = -1
multiply both sides by minus sign
-(-x²) = -(-1)
x² = 1
take square root of both sides;
√x² = ±√1
x = ±1
x = 1 and x = -1
when x = 1
f(x) = y = 1-1²
y = 1-1
y = 0
when x = -1
f(x) = y = 1-(-1)²
y = 1-1
y = 0
Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)
Yes the ratio would change because it needs 3 times more than the original amount so you would multiply it by 3
Answer:

And then replacing in the total probability formula we got:

And rounded we got 
That represent the probability that it rains over the weekend (either Saturday or Sunday)
Step-by-step explanation:
We can define the following notaton for the events:
A = It rains over the Saturday
B = It rains over the Sunday
We have the probabilities for these two events given:

And we are interested on the probability that it rains over the weekend (either Saturday or Sunday), so we want to find this probability:

And for this case we can use the total probability rule given by:

And since we are assuming the events independent we can find the probability of intersection like this:

And then replacing in the total probability formula we got:

And rounded we got 
That represent the probability that it rains over the weekend (either Saturday or Sunday)
Answer:
The third one
Step-by-step explanation: