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mr_godi [17]
2 years ago
15

The support pole of the tent shown forms one leg of a right triangle. One side of the tent forms the hypotenuse of the right tri

angle. Find the length of the base of the tent.
Someone please helpppp!!!!1

Mathematics
1 answer:
svetoff [14.1K]2 years ago
8 0
Ans=24
You need to use Pythagorean theorem.
A^2+b^2=c^2
X^2+32^2=40^2
X^2+1024=1600
1600-1024=576
576=x^2
Square root of 576=x=24
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2 equivalent forms of 0.7875
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Idk what that answer is soooo
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3 years ago
Please help!<br> Subtract h + 3 ​​from​ 6h + 1.
cricket20 [7]
6h+1-h+3
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4 0
3 years ago
A rectangle has an area of 96 cm2 The length of the rectangle is 4 cm longer than the width. Work out the length and width of th
Svetach [21]
Area of a rectangle: 2(L+W)
length: 4+W

Area: 2(4+W) + 2W = 96
8+2W+2W = 96
8+4W = 96
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W= 22cm

Calculate for length: 2L + 2(22) = 96
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3 0
3 years ago
A rectangle has a width of 2cm and a perimeter of 25cm. Find the length and the area .
Gwar [14]

2w + 2l = 25

2 * 2 + 2l = 25

<em><u>Simplfiy.</u></em>

4 + 2l = 25

<em><u>Subtract 4 from both sides.</u></em>

2l = 21

<em><u>Divide both sides by 2.</u></em>

l = 10.5

Now that we have the value of l, we can find the area.

A = lw

A = 10.5 * 2

A = 21.

The length is 10.5cm.

The area of the rectangle is 21cm^2

5 0
3 years ago
Due to weather mark walk to school day of the 20 days in february what would be the fraction representation for the number of da
nekit [7.7K]

Tbe question doesn't state the number of days he walked to school out of 20 school days in the

Month of February.

Answer:

Kindly check explanation

Step-by-step explanation:

To. Obtain the fractional representayion for the number of days he walked to school ;

Let the number of days he walked to school = 10 (this is an hypothesized value)

Number of school days in February = 20

Fraction = 10 /20 = 0.5

The percentage of times walked to school : multiply the fraction obtained above by 100%

0.5 * 100% = 50%

Just put the desired value and proceed uSing the steps described above.

8 0
3 years ago
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