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Vaselesa [24]
3 years ago
5

Let U = {1, 2, 3, 4, 5, 6, 7), A = {2, 4, 6, 7), and B = {1, 4, 7}. Find the set (A U B)'.​

Mathematics
1 answer:
den301095 [7]3 years ago
3 0

Step-by-step explanation:

(A U B) = {1,2, 4, 6, 7}

(A U B)'= U- (A U B) = { 3,5}<------- Answer

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Describe how the graphs of square root and cube root functions are similar and how they are different.
Molodets [167]

Answer:

Just as the square root is a number that, when squared, gives the radicand, the cube root is a number that, when cubed, gives the radicand. Cubing a number is the same as taking it to the third power: 23 is 2 cubed, so the cube root of 23 is 2.

Step-by-step explanation:

there i hope you understood

5 0
3 years ago
Read 2 more answers
PLEASE HELP QUICKLY<br> What is the value of y
Sidana [21]

Answer:

y= 8

Step-by-step explanation:

In a Triangle we know,

W+Y+X=180 degree

then,

(180-52)+(4y-4)+3y=180

or, 128+4y-4+3y= 180

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4 0
2 years ago
Consider the function f ( x ) = − 2 x 3 + 27 x 2 − 108 x + 9 . For this function there are three important open intervals: ( − [
Darya [45]

Answer:

<em>A=3 and B=6</em>

Step-by-step explanation:

<u>Increasing and Decreasing Intervals of Functions</u>

Given f(x) as a real function and f'(x) its first derivative.

If f'(a)>0 the function is increasing in x=a

If f'(a)<0 the function is decreasing in x=a

If f'(a)=0 the function has a critical point in x=a

As we can see, the critical points may define open intervals where the function has different behaviors.

We have

f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9

Computing the first derivative:

f' ( x ) = - 6 x^3 + 54 x - 108

We find the critical points equating f'(x) to zero

- 6 x^3 + 54 x - 108=0

Simplifying by -6

x^2 -9 x +18=0

We get the critical points

x=3,\ x=6

They define the following intervals

(-\infty,3),\ (3,6),\ (6,+\infty)

Thus A=3 and B=6

3 0
3 years ago
What value is the cube root of 27
umka21 [38]
3 is the cube root of 27
7 0
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zloy xaker [14]

Answer:

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Step-by-step explanation:

4 0
3 years ago
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