Number one is c. It should take her about nine days
If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.
Given that m∠ABF=41° and BF is an angle bisector.
We are required to find the angle m∠BCE if BF is an angle bisector.
Angle bisector basically divides an angle into two parts.
If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.
In this way ∠ABC=2*∠ABF
∠ABC=2*41
=82°
In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.
∠BCE+∠CEB+EBC=180 (Sum of all the angles in a triangle is 180°)
∠BCE+90+82=180
∠BCE=180-172
∠BCE=8°
Hence if BF is an angle bisector then angle m∠BCE=8°.
Learn more about angles at brainly.com/question/25716982
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Answer:
y = -9/10x + 3/10 or y = 3/10(1 - 3x)
Step-by-step explanation:
Perpendicular lines have slopes that are negative reciprocals of one another
so slope of line w is -9/10
Using (-3,3) >> y = -9/10x + b
3 = -9/10(-3) + b
3 = 27/10 + b
b = 3 - 27/10 = 30/10 - 27/10 = 3/10
y = -9/10x + 3/10 or y = 3/10(1 - 3x)
K is 'angle bisector' because it seperated the angle's center.
Hope it helps!
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