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3 years ago

If FGH QRS, find the measure of Q A. 9 B.28 C.11 D.34

Mathematics

1 answer:

Ne4ueva [31]3 years ago

6 0

Answer:

28°

Step-by-step explanation:

Since ΔFHG ≅ QRC, the corresponding angles are congruent:

∠F = ∠Q
(2x + 10)° = (3x + 1)°
3x - 2x = (10 - 1)°
x = 9°

Then, the angle Q measures:

∠Q = (3*9 + 1)° = 28°

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Please notice that $x^{2}+3\cdot x + 9$ have two complex roots.

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We kindly invite to see this question on polynomials: brainly.com/question/1218505

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