3 years ago

If FGH QRS, find the measure of Q A. 9 B.28 C.11 D.34

Mathematics

1 answer:

Ne4ueva [31]3 years ago

6 0

Answer:

28°

Step-by-step explanation:

<u>Since ΔFHG ≅ QRC, the corresponding angles are congruent:</u>

∠F = ∠Q
(2x + 10)° = (3x + 1)°
3x - 2x = (10 - 1)°
x = 9°

<u>Then, the angle Q measures:</u>

∠Q = (3*9 + 1)° = 28°

You might be interested in

What is the angle measure of an arc bounding sector with an area of 5pie square miles?

Snowcat [4.5K]

if the diameter is 20, the its radius must be half that or 10.

$\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta \pi r^2}{360}~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ A=5\pi \\ r=10 \end{cases}\implies \begin{array}{llll} 5\pi =\cfrac{\theta \pi (10)^2}{360}\implies 5\pi =\cfrac{5\pi \theta }{18} \\\\\\ \cfrac{5\pi }{5\pi }=\cfrac{\theta }{18}\implies 1=\cfrac{\theta }{18}\implies 18=\theta \end{array}$