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fredd [130]
2 years ago
5

write the equation of the line, in standard form, that is perpendicular to y=3x-2 and passes through (-7,2)

Mathematics
1 answer:
34kurt2 years ago
8 0

Answer:

x+3y=-1

Step-by-step explanation:

y=3x-2 so m=3 old slope

the new slope must be -1/3 (opposite reciprocal of the old slope).

y-y0=m*(x-x0)

y-2=-1/3*(x-(-7))

y-2=-1/3x-1/3*7

y-2=-1/3x-7/3

3y-6=-x-7

The standard form for linear equations in two variables is Ax+By=C.

x+3y=6-7

x+3y=-1

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kykrilka [37]

If you would like to know what is f(2), you can calculate this using the following steps:<span>

f(0) = 2
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3 years ago
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