Answer:
Total length of iron needed to make the square frame and two diagonals = 43.44 in (Approx)
Step-by-step explanation:
Given:
Length of diagonal = 9 in
Find:
Total length of iron needed to make the square frame and two diagonals.
Computation:
Area of square = 1/2(diagonal)²
Area of square = 1/2(9)²
Area of square = 40.5 in²
Area of square = Side × Side
40.5 in² = Side × Side
Side = 6.36 (approx)
Total length of iron needed to make the square frame and two diagonals = Permeter of square + (2 × diagonal)
⇒ (4 × 6.36) + (2 × 9)
⇒ (25.44) + (18)
⇒ 43.44 in
Total length of iron needed to make the square frame and two diagonals = 43.44 in (Approx)
Step-by-step explanation:
If T:Rn→Rm is a linear transformation and if A is the standard matrix of T, then the following are equivalent:
1. T is one-to-one.
2. T(x) = 0 has only the trivial solution x=0.
3. If A is the standard matrix of T, then the columns of A are linearly independent.
Here, A is a mxn matrix where m ≥ n and the rank of A equals n. It implies that the columns of A are linearly independent, for, otherwise, the rank of A would be less than n. Hence the linear transformation represented by A is one-to-one.
Answer: =13n+2y+1/4
Step-by-step explanation: Hope this help :D
Let simplify step by step
9n+1/4+6y+4n-4y
=9n+1/4+6y+4n-4y
combine like terms:
=9n+1/4+6y+4n+-4y =(9n+4n) +(6y+-4y) +(1/4)
=13n+2y+1/4 Hope
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Explanation:</h2><h2>
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By using quadratic formula:
So the solutions are:
M = -2 is da answer to da equation
