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sweet [91]
3 years ago
5

Find the zeros for: f(x)=x^4+x^3+4x^2 (Please show work)

Mathematics
2 answers:
mixas84 [53]3 years ago
6 0

View the image to see how I solved this problem.

Tanya [424]3 years ago
6 0

There is an obvious factor of x², so we can reduce this to the problem of finding zeros of a quadratic by factoring that out. Then, we can determine the zeros of the quadratic factor to complete the finding of zeros for the function.

A factor of x² can be factored out, leaving ...

... f(x) = x²(x² +x +4)

The latter factor has only complex zeros. It can be rewritten by completing the square.

... x² +x +4 = (x² +x +1/4) +(3 3/4) = (x +1/2)² +(3 3/4)

So, the real zeros are where x² = 0, at x = 0. The complex zeros are where the above expression is zero, ...

... (x +0.5)² +3.75 = 0

... (x +0.5)² = -3.75

... x + 0.5 = √-3.75 = ±0.5i√15

... x = -0.5(1 ±i√15)

The function zeros are 0 (multiplicity 2) and -0.5±0.5i√15.

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I NEED HELP!!! 12 PTS!!!
Agata [3.3K]
The answer is 13 packages.
6 0
3 years ago
Read 2 more answers
Please help me thank you!
sergiy2304 [10]

Answer:

The equation of the line that passes through the points

(5,2) and (-5,6)

is

y=-2/5x+4

Step-by-step explanation:

You want to find the equation for a line that passes through the two points:

(5,2) and (-5,6).

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (5,2), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=5 and y1=2.

Also, let's call the second point you gave, (-5,6), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=-5 and y2=6.

Now, just plug the numbers into the formula for m above, like this:

m= 6 - 2/-5 - 5 or m= 4-10 or m=-2/5

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-2/5x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(5,2). When x of the line is 5, y of the line must be 2.

(-5,6). When x of the line is -5, y of the line must be 6.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=-2/5x+b. b is what we want, the -2/5 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (5,2) and (-5,6).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(5,2). y=mx+b or 2=-2/5 × 5+b, or solving for b: b=2-(-2/5)(5). b=4.

(-5,6). y=mx+b or 6=-2/5 × -5+b, or solving for b: b=6-(-2/5)(-5). b=4.

3 0
2 years ago
1. If f(x) = 2x - 3, find the following:<br> a. f(-2) =<br> b. f(7) =<br> c. f(-4) =
Pavlova-9 [17]
A. 2(-2) - 3
-4 - 3
-7

b. 2(7) - 3
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11

2(-4) - 3
-8 - 3
- 11
5 0
2 years ago
Expand (x-2)^7 using binomial theorem​
umka2103 [35]

Answer:

Urr answer...

Step-by-step explanation:

<h3 /><h3 /><h3 /><h3 /><h3>i hope its help to you ✌</h3>

4 0
2 years ago
Read 2 more answers
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astra-53 [7]
12.25 is the scale factor if the pre image is 12 and the image is 147
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