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Anna [14]
2 years ago
14

PLS HELP I WILL GIVE BRAINLIEST 1- If you are driving at a constant speed of 55 miles per hour, give an estimate of how many mil

es you will travel in 1 hour and 20 minutes.
2-Anthony paid $36.25 for about 11.5 gallons of gas. Estimate the price for one gallon of gas.

Write an expression that represents each statement.
3.The total cost of my cell phone bill for the 1st month, if I am charged a standard installation fee of $50 plus .50 cents for each channel that I have in my package.
Mathematics
1 answer:
Hatshy [7]2 years ago
8 0

Answer:

1- 72 miles

2-$3

3- 50(0.50 x c)

Step-by-step explanation:

For Number 1 we have to do 55 divided by 60 which is about 0.90 and then we multiply that by 1 hour and 20 minutes which in minutes is 80. 0.90 x 80 = 72 exactly.

For Number 2 we have to divide 36.25 by 11.5 rounded is 36/12 whish is 3.

For number 3 c stands for number of channels

Hope i could help! :DD

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What statement is always true? A the sum of 2 irrational numbers is rational B the product of 2 irrational numbers is rational C
Akimi4 [234]

I think the answer is D. but I'm not sure.

7 0
3 years ago
What does 4(m-2)=2(m-9) equal
marshall27 [118]

Answer:

m = -5

Step-by-step explanation:

Simplify both sides of the equation.

4(m−2)=2(m−9)

(4)(m)+(4)(−2)=(2)(m)+(2)(−9)(Distribute)

4m+−8=2m+−18

4m−8=2m−18

Subtract 2m from both sides.

4m−8−2m=2m−18−2m

2m−8=−18

Add 8 to both sides.

2m−8+8=−18+8

2m=−10

Divide both sides by 2.

2m/2 = -10/2

m = -5

3 0
3 years ago
Two particles travel along the space curves r1(t) = t, t2, t3 r2(t) = 1 + 2t, 1 + 6t, 1 + 14t . Find the points at which their p
GuDViN [60]

Answer:

A) points at which paths intersect : (1,1,1) ; (2,4,8)

B) DNE

Step-by-step explanation:

A) To find the points in which the particle paths intersect, it is necessary to find the values of t for which the three components of both vectors are equal:

t_1=1+2t_2\\\\t_1^2=1+6t_2\\\\t_1^3=1+14t_2

you replace t1 from the first equation in the second equation:

(1+2t_2)^2=1+6t_2\\\\1+4t_2+4t_2^2=1+6t_2\\\\4t_2^2-2t_2=0\\\\t_2(2t_2-1)=0\\\\t_2=0\\\\t_2=\frac{1}{2}

Then, for t2 = 0 and t2=1/2 you obtain for t1:

t_1=1+2(0)=1\\\\t_1=1+2(\frac{1}{2})=2

Hence, for t1=1 and t2=0 the paths intersect. Furthermore, for t1=2 and t2=1/2 the paths also intersect.

The points at which the paths  intersect are:

r_1(1)=(1,1,1)=r_2(0)=(1,1,1)\\\\r_1(2)=(2,4,8)=r_2(\frac{1}{2})=(2,4,8)

B) You have the following two trajectories of two independent particles:

r_1(t)=(t,t^2,t^3)\\\\r_2(t)=(1+2t,1+6t,1+14t)

To find the time in which the particles collide, it is necessary that both particles are in the same position on the same time. That is, each component of the vectors must coincide:

t=1+2t\\\\t^2=1+6t\\\\t^3=1+14t

From the first equation you have:

t=1+2t\\\\t=-1

This values does not have a physical meaning, then, the particle do not collide

answer: DNE

5 0
3 years ago
10. Melissa has $20 to buy bagels and juice for her class. box of bagels bottle of juice 56.13, including tax $2.08, including t
adelina 88 [10]

The inequality for the maximum number of bottles of juice she can buy

6.13+ 2.08b <20.00

Option B

Given

Melissa has $20 to buy bagels and juice for her class

Box of bagels :   6.13 including tax

Bottle of juice: 2.08 including tax

She will buy only one box of bagels that is for 6.13

Let 'b' be the number of bottles of juice she can buy

Total cost should be less than 20 dollars

6.13(one bagels) +2.08(bottles of juices)<20

So the inequality becomes

6.13+2.08b

Learn more :  brainly.com/question/1836165

4 0
2 years ago
Please help me: Ten athletes ran two races of the same length. The scatter plot shows their times. Identify each of these statem
Lemur [1.5K]

The scatter plot has been attached

Answer:

Options C, D & E are true

Step-by-step explanation:

Option A is wrong because from the scatter plot, only four athletes were faster in the second race than in the first one.

Option B is wrong because only 1 athlete had his second race time differing from the first race time by exactly 2 seconds.

Option C is true because exactly 9 of the times for the first race were at least 16 seconds

Option D is true because there are exactly 3 athletes who had the same time in both races

Option E is true because 8 of the times for the second race were less than 17 seconds

4 0
3 years ago
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