The diagonal of a rectangle = sqrt(w^2 + l^2)
w = width
l = length
In this problem,
The diagonal = 20 in
w = x
l = 2x + 8
Let's plug our numbers into the formula above.
20in = sqrt((x)^2 + (2x + 8)^2)
Let's simplify the inside of the sqrt
20 in = sqrt(5x^2 + 32x + 64)
Now, let's square both sides.
400 = 5x^2 + 32x + 64
Subtract 400 from both sides.
0 = 5x^2 + 32x - 336
Factor
0 = (5x - 28)(x + 12)
Set both terms equal to zero and solve.
x + 12 = 0
Subtract 12 from both sides.
x = -12
5x - 28 = 0
Add 28 to both sides.
5x = 28
Divide both sides by 5
x = 28/5
The width cant be a negative number so now we know that the only real solution is 28/5
Let's plug 28/5 into our length equation.
Length = 2(28/5) + 8 = 56/5 + 8 = 96/5
In conclusion,
Length = 96/5 inches
Width = 28/5
Answer:
- 6x² - 2x + 1
Step-by-step explanation:
Given
(2x³ - 4x² - 3x + 5) + (- 2x³ - 2x² + x - 4)
Both parenthesis are distributed by 1 thus just remove them
= 2x³ - 4x² - 3x + 5 - 2x³ - 2x² + x - 4 ← collect like terms
= - 6x² - 2x + 1
Answer:
D is the answers for the question
Step-by-step explanation:
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Answer:
For the second one: NO congruent to MO.
For the third one: angle N congruent to angle O.
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