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gayaneshka [121]
3 years ago
12

Find the measure of the numbered angle m<2

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
5 0
130 degrees yuhhhhhhhh
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Help please please please and thank you ʕ•ᴥ•ʔ
SSSSS [86.1K]

Answer:

Solve 3x+10+8x-17=180 to get x, then take the value of 8x-17 and set that equal to 6y+11 to get y.

Step-by-step explanation:

Solve 3x+10+8x-17=180 because the 3x+10 is the same angle as the one right under the 8x-17 angle because they are corresponding angles with lines that are parallel. Then, take the value of 8x-17 = 6y+11 because they are vertical angles.

5 0
3 years ago
4 2/3 divided by 1/4 = idk help me for 32 points
WARRIOR [948]

18 2/3

Answer:

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Mrs morals wrote a test with 15 questions covering spelling and vocabulary. Spelling questions (x) are worth 5 points and vocabu
erastova [34]

Answer:

Step-by-step explanation:

Let x represent the number of spelling questions in the test.

Let y represent the number of vocabulary questions in the test.

Mrs morals wrote a test with 15 questions covering spelling and vocabulary. This means that

x + y = 15

Spelling questions (x) are worth 5 points and vocabulary questions (y) are worth 10 points. The maximum number of points possible on the test is 100. This means that

5x + 10y = 100 - - - - - - - - - - - 1

Substituting x = 15 - y into equation 1, it becomes

5(15 - y) + 10y = 100

75 - 5y + 10y = 100

- 5y + 10y = 100 - 75

5y = 25

y = 25/5 = 5

x = 15 - y = 15 - 5 = 10

4 0
4 years ago
***BRAINLIEST ANSWER**
Marrrta [24]

Answer:

130°

Step-by-step explanation:

Arc QPN is formed by angle QNT. Angle QNT is formed by an intersecting tangent and chord meaning arc QPN is two times the measure of angle QNT.

65° · 2 = 130°

4 0
3 years ago
Find the greatest common factor of the following monomials u^2v^5 and 12u^4v^5
kifflom [539]

Answer:

The greatest common factor would be u^2v^5

Step-by-step explanation:

To find the greatest common factor, simply count the lowest number of each term between the two monomials.

For u's, there are 2 in the first term and 4 in the second. So we take out u^2.

For v's, there are 5 in both, so we take out v^5.

4 0
4 years ago
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