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Elena L [17]
3 years ago
15

In triangle ABC, what is the measure of angle Cif A = 85°, a = 35, and c = 25?

Mathematics
2 answers:
Wittaler [7]3 years ago
8 0

Answer:

yes

Step-by-step explanation:

yes

blondinia [14]3 years ago
5 0

yes the answer is C = 25

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A rhombus has four 6-inch sides and two 120-degree angles. From one of the vertices of the obtuse angles, the two latitudes are
nikitadnepr [17]

Answer:

Area(A)=Area(C)= 9 in^{2}

Area(B)=13.2 in^{2}

Step-by-step explanation:

We begin with finding the angles a and b that from the drawing attached you can see that a=b.

Now, the sum of the internal angles of a rhomboid is equal to 360 degrees, with that we have:

120+120+a+b=360

240+2a=360

2a=120

a=60=b

Next, in the image you can see that the lines coming from the angle at the top 120 degrees vertex, divide the opposite sides by half, thus making two triangles with one side of 6 in and another of 3 in.

We can say from the drawing as well:

Area(A)+Area(B)+Area(C)=Area(rhomboid)

But, we can also say that Area(A)=Area(C)

So, starting with Area(A)

Area(A)=Area(triangle)=\frac{b*h}{2}=\frac{6*3}{2}=9 in^{2}

We can then calculate the area B, a rhomboid, or better, take the Total area of the figure and subtract the area of the two triangles.

Area(B)=Area(rhomboid)-Area(A)-Area(C)

Area(rhomboid)=b*h where b=6in and h is the perpendicular distance from the base to the top.

h=[tex]6*cos(30)=5.20in   The 30 degrees come from: 120-30-60=30, since the latitudes split the 120 angle in two equal parts and one that is the half of the obtuse angle.

Area(rhomboid)=5.20*6=31.2 in^{2}

Area(B)=Area(rhomboid)-Area(A)-Area(C)=31.2 in^{2}-9 in^{2}-9 in^{2}=13.2 in^{2}

3 0
3 years ago
The amount of lateral expansion (mils) was determined for a sample of n = 8 pulsed-power gas metal arc welds used in LNG ship co
Alona [7]

Answer:

95% Confidence interval for the variance:

3.6511\leq \sigma^2\leq 34.5972

95% Confidence interval for the standard deviation:

1.9108\leq \sigma \leq 5.8819

Step-by-step explanation:

We have to calculate a 95% confidence interval for the standard deviation σ and the variance σ².

The sample, of size n=8, has a standard deviation of s=2.89 miles.

Then, the variance of the sample is

s^2=2.89^2=8.3521

The confidence interval for the variance is:

\dfrac{ (n - 1) s^2}{ \chi_{\alpha/2}^2} \leq \sigma^2 \leq \dfrac{ (n - 1) s^2}{\chi_{1-\alpha/2}^2}

The critical values for the Chi-square distribution for a 95% confidence (α=0.05) interval are:

\chi_{0.025}=1.6899\\\\\chi_{0.975}=16.0128

Then, the confidence interval can be calculated as:

\dfrac{ (8 - 1) 8.3521}{ 16.0128} \leq \sigma^2 \leq \dfrac{ (8 - 1) 8.3521}{1.6899}\\\\\\3.6511\leq \sigma^2\leq 34.5972

If we calculate the square root for each bound we will have the confidence interval for the standard deviation:

\sqrt{3.6511}\leq \sigma\leq \sqrt{34.5972}\\\\\\1.9108\leq \sigma \leq 5.8819

6 0
3 years ago
To prove ABC= ADC, To prove which triangle postulate could you use?
Kay [80]

Answer:

ASA

Step-by-step explanation:

..................

6 0
3 years ago
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What is a simplified expression for (x−y)−(x+y)?
stellarik [79]

Answer:

-2y

Step-by-step explanation:

Let's simplify step-by-step.

x−y−(x+y)

Distribute the Negative Sign:

=x−y+−1(x+y)

=x+−y+−1x+−1y

=x+−y+−x+−y

Combine Like Terms:

=x+−y+−x+−y

=(x+−x)+(−y+−y)

=−2y

3 0
3 years ago
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A triangle is inscribed in a rectangle as shown below what is the area of the shaped region
alekssr [168]

Answer:

Step-by-step explanation:

area of rectangle=11×5=55 cm²

area of triangle=1/2×5×3=15/2=7.5 cm²

area of shaded region=55-7.5=47.5 cm²

6 0
3 years ago
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