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vfiekz [6]
2 years ago
13

A little help plssss

Mathematics
2 answers:
evablogger [386]2 years ago
7 0
26 is the answer or perimeter
MariettaO [177]2 years ago
4 0

Answer:

26 This is perimeter

Step-by-step explanation:

Perimeter= Add up all the outside numbers

Area= Length x width

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Find a​ point-slope form for the line with slope 1/5 and passing through the point ​(-7​,-6​).
KiRa [710]
The equation for this would be:
y+6= 1/5(x+7)
5 0
3 years ago
I
posledela

Answer:

6(x-8)=5-2x

Step-by-step explanation:

let the number be x

so we have six times the difference between a number and 8

that is 6(x-8).

is equal to 5 less than twice the number ..we have

=5-2x.

therefore, our answer becomes:

6(x-8)=5-2x

5 0
3 years ago
Write the equation of the circle whose center is (-5, -8) with diameter 12
lora16 [44]

Answer:

(x + 5)^2 + (y + 8)^2 = 6^2

Step-by-step explanation:

A circle formula: (x - h)^2 + (y - k)^2 = r^2

We are given diameter. To find the radius divide diameter by 2.

d = 12

12/2 = r = 6

H and K are given to be (-5 , -8)

(x - (-5))^2 + (y - (-8))^2 = 6^2

(x + 5)^2 + (y + 8)^2 = 6^2

I have plot this equation to confirm my answer is correct where the origin is (-5 , -8) and has a radius of 6.

3 0
2 years ago
Marta's dog just had six puppies. Four are female (F), and two are male (M). One of the males is brown. Two of the females are b
kondaur [170]
Male is 66% brown is 50% both is 58% and there are two male puppies
8 0
3 years ago
Read 2 more answers
What function corresponds to the ordered pairs shown in the table?
Anettt [7]

well, we know it's a line, and to get the equation of any line all we need is two points, let's pick two from the table hmmmm say let's use (-3 , -7) and (3 , 11)

(\stackrel{x_1}{-3}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{11}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{11}-\stackrel{y1}{(-7)}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{(-3)}}}\implies \cfrac{11+7}{3+3}\implies \cfrac{18}{6}\implies 3

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-7)}=\stackrel{m}{3}(x-\stackrel{x_1}{(-3)}) \\\\\\ y+7=3(x+3)\implies y+7=3x+9\implies y = 3x+2

6 0
3 years ago
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