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zhuklara [117]
3 years ago
14

Can anyone help with this question

Mathematics
2 answers:
timurjin [86]3 years ago
8 0

Answer:

162, sorry if this is wrong

Step-by-step explanation:

finlep [7]3 years ago
3 0
It rigt thi answer above is correct i shek
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jen butler has beeb pricing speed-pass train fares for a group trip to new york. three adults and four children must pay $80. tw
Degger [83]

Answer:

Adult price is: $12

Children price is: $11

3 0
3 years ago
angle A and angle B are supplementary angles. If m angle A=(7x+14)^ and m angle B=(5x-26)^ , then find the measure of angle B .
Aleksandr [31]

Answer:

35x^2 - 112x - 364

it's probably wrong since I've only expanded the brackets

5 0
3 years ago
Help me find a trend line for the data.
Hatshy [7]

A linear equation of the trend line that models the data points contained in the table is y = 0.09x + 16.27.

<h3>How to find a trend line for the data?</h3>

In order to determine a linear equation of the trend line (line of best fit) that models the data points contained in the table, we would have to use a scatter plot.

In this scenario, the body weight (in lbs) of the high school students would be plotted on the x-axis of the scatter plot while the backpack weight (in lbs) would be plotted on the y-axis of the scatter plot.

On the Excel worksheet, you should right click on any data point on the scatter plot, select format trend line, and then tick the box to display an equation for the trend line (line of best fit) on the scatter plot.

From the scatter plot (see attachment) which models the relationship between data points in the table, a linear equation of the trend line is given by:

y = 0.09x + 16.27

Read more on scatter plot here: brainly.com/question/28605735

#SPJ1

7 0
1 year ago
Construct a 95% confidence interval for the population mean, µ. Assume the population has a normal distribution. A sample of 25
bixtya [17]

Answer:C. (77.29, 85.71)

Step-by-step explanation:

We want to determine a 95% confidence interval for the mean test score of randomly selected students.

Number of sample, n = 25

Mean, u = 81.5

Standard deviation, s = 10.2

For a confidence level of 95%, the corresponding z value is 1.96. This is determined from the normal distribution table.

We will apply the formula

Confidence interval

= mean +/- z ×standard deviation/√n

It becomes

81.5 +/- 1.96 × 10.2/√25

= 81.5 +/- 1.96 × 2.04

= 81.5 +/- 3.9984

The lower end of the confidence interval is 81.5 - 3.9984 =77.5016

The upper end of the confidence interval is 81.5 + 3.9984 =85.4984

Therefore, the correct option is

C. (77.29, 85.71)

6 0
3 years ago
Plzzzzzzzzzzzzz help
9966 [12]
2/12 + 6/12 = 8/12 / 4/4 = 2/3. 2/3 of an hour.
7 0
3 years ago
Read 2 more answers
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