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I am Lyosha [343]

3 years ago

13

A bird at the top of a tree looks down at a field mouse with an angle of depression of 65Á. If the field mouse is 30 meters from

the base of the tree, find the distance from the field mouse to the birdÍs eyes. Round the answer to the nearest tenth.
a.
29.6 m
b.
50.0 m
c.
64.3 m
d.
71.0 m

1 answer:

Dafna11 [192]3 years ago

3 0

Correct answer is 33.1 m.

Use The definition of trigonometric functions. The sine of an angle is the quotient of the opposite side and hypotenuse.

$sin{65^o}= \frac{30}{x} 
\\x= \frac{30}{sin{65^o}}
\\x=33.1 
$

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Which of the following would best represent a cosine function with an amplitude of 3, a period of pi/2 , and a midline at y = –4

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To transform the function $f(x)= cos(x)$ to have the amplitude of 3, we need to multiply the constant 3 to the function f(x), so we have $y=3f(x)$

To transform the function $f(x)=cos(x)$ to have the midline $y=-4$ we need to subtract $f(x)$ by 4, so we have $y=f(x)-4$ ,

To transform the function $f(x)=cos(x)$ to have period of $\frac{ \pi }{2}$ , we need to divide the original period $2 \pi$ by 4, so we have $y=f(4x)$ . Note that it is the $4x$ gives the effect of dividing the points on x-axes by 4 and the period is read on x-axes

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The sugar content of the syrup in canned peaches is normally distributed. A random sample of n = 10 cans yields a sample standar

Serggg [28]

Answer:

The 95% confidence interval is given by:

3.30<σ<8.76

Step-by-step explanation:

1) Data given and notation

s=4.798 represent the sample standard deviation

$\bar x$ represent the sample mean

n=10 the sample size

Confidence=95% or 0.95

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=10-1=9$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a tabel to find the critical values.

The excel commands would be: "=CHISQ.INV(0.025,9)" "=CHISQ.INV(0.975,9)". so for this case the critical values are:

$\chi^2_{\alpha/2}=19.022$

$\chi^2_{1- \alpha/2}=2.700$

And replacing into the formula for the interval we got:

$\frac{(9)(4.798)^2}{19.022} \leq \sigma \frac{(9)(4.798)^2}{2.700}$

$10.892 \leq \sigma^2 \leq 76.736$

Now we just take square root on both sides of the interval and we got:

$3.30 \leq \sigma \leq 8.76$

So the best option would be:

3.30<σ<8.76

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