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Ne4ueva [31]
3 years ago
6

5x - Зу = 2 Find the slope of this equation

Mathematics
2 answers:
torisob [31]3 years ago
8 0
The slope is 5/3 and the y- intercept is -2/3
nirvana33 [79]3 years ago
5 0

Step-by-step explanation:

calculate this equation to y:

5x - 3y = 2

<=> 3y = 5x - 2

<=> y = 5/3x - 2/3

the slope is the value at x, so in this case 5/3

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andriy [413]
Addition, I would use the principles of addition. 
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3 years ago
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Plz help and thank you
Nataliya [291]
A. w= 2 /12..........
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The ratio of the measures of the sides of a triangle is 3:4:5. Its perimeter is 48 inches. Find the scale factor as a decimal, a
Trava [24]

Given:

The ratio of the measures of the sides of a triangle is 3:4:5.

Its perimeter is 48 inches.

To find:

The scale factor as a decimal, and the measure of each side of the triangle.

Solution:

Let x be the scale factor. Then the measures of sides of the triangle are 3x, 4x and 5x.

The perimeter of the triangle is 48 inches. It means the sum of all sides of the triangle is 48 inches.

3x+4x+5x=48

12x=48

Divide both sides by 12.

x=\dfrac{48}{12}

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Now, the measures of sides are:

3x=3(4)

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Similarly,

4x=4(4)

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And,

5x=5(4)

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Therefore, the scale factor is 4 and the measures of sides are 12, 16 and 20.

5 0
3 years ago
Read 2 more answers
How can we get Equation B from Equation A? A. 5 = -2 (x - 1) B. 5 = -2x + 2 How can we get Equation B from Equation A?
lesya [120]

Answer:

Please check the explanation.

Step-by-step explanation:

<u>Determining equation B from Equation A</u>

Given the equation A

5\:=\:-2\:\left(x\:-\:1\right)

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5= -2x+2    which is equation B

Hence, equation B can be obtained by implementing the distributive law operation on equation A.

<u>Determining equation A from Equation B</u>

Given the equation B

5 = -2x + 2

Factor out common term -2 on the right-hand side of the equation

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Hence, equation A can be obtained by factoring out the common term -2 on the right-hand side of equation B.

7 0
2 years ago
Integrate sin²2x cos²2x dx
DochEvi [55]
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\cos^2x=\dfrac{1+\cos2x}2

From the identities above, you have

\sin^22x\cos^22x=\dfrac{(1-\cos4x)(1+\cos4x)}4=\dfrac{1-\cos^24x}4

Applying once more, you have

\dfrac{1-\cos^24x}4=\dfrac{1-\dfrac{1+\cos8x}2}4=\dfrac{1-\cos8x}8

So,

\displaystyle\int\sin^22x\cos^22x\,\mathrm dx=\frac18\int(1-\cos8x)\,\mathrm dx=\frac x8-\frac1{64}\sin8x+C
7 0
3 years ago
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