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2 years ago

5x - Зу = 2 Find the slope of this equation

Mathematics

2 answers:

torisob [31]2 years ago

8 0

The slope is 5/3 and the y- intercept is -2/3

nirvana33 [79]2 years ago

5 0

Step-by-step explanation:

calculate this equation to y:

5x - 3y = 2

<=> 3y = 5x - 2

<=> y = 5/3x - 2/3

the slope is the value at x, so in this case 5/3

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Given the inequality: m − 11 ≤ 16 or 15 − 2m < −7 Solve for j and graph the solution on a number line. Must show your work to

Olenka [21]

Answer:

m ≤ 27 or m > 11

m is all real number since we have the or

Step-by-step explanation:

m − 11 ≤ 16 or 15 − 2m < −7

Lets solve the one on the left first

m − 11 ≤ 16

Add 11 to each side

m-11+11 ≤ 16 +11

m ≤ 27

Now lets solve the one on the right

15 − 2m < −7

Subtract 15 from each side

15 −15- 2m < −7 -15

-2m < -22

Divide by -2, remembering to flip the inequality

-2m/-2 > -22/-2

m > 11

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3 years ago

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B. I don't know

Step-by-step explanation:

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2 years ago

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tester [92]

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3 years ago

Which proportion is NOT true?

Ira Lisetskai [31]

Answer:

I think its BD/FG=AD/EH.

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2 years ago

What is the form of the two squares identity?

zvonat [6]

Answer:

Step-by-step explanation:

Consider all options:

A. False, because

$(a^2+b^2)(c^2+d^2)=a^2c^2+a^2d^2+b^2c^2+b^2d^2\\ \\(ab-cd)^2+(ac+bd)^2=a^2b^2-2abcd+c^2d^2+a^2c^2+2abcd+b^2d^2=\\ =a^2b^2+c^2d^2+a^2c^2+b^2d^2\\ \\a^2c^2+a^2d^2+b^2c^2+b^2d^2\neq a^2b^2+c^2d^2+a^2c^2+b^2d^2$

B. False, because

$(a^2-b^2)(c^2+d^2)=a^2c^2+a^2d^2-b^2c^2-b^2d^2\\ \\(ac-bd)^2-(ad+bc)^2=a^2c^2-2abcd+b^2d^2+a^2d^2+2abcd+b^2c^2=\\=a^2c^2+b^2d^2+a^2d^2+b^2c^2\\ \\a^2c^2+a^2d^2-b^2c^2-b^2d^2\neq a^2c^2+b^2d^2+a^2d^2+b^2c^2$

C. False, because

$(a^2+b^2)(c^2-d^2)=a^2c^2-a^2d^2+b^2c^2-b^2d^2\\ \\(ac+bd)^2-(ad+bc)^2=a^2c^2+2abcd+b^2d^2-a^2d^2-2abcd-b^2c^2=\\=a^2c^2+b^2d^2-a^2d^2-b^2c^2\\ \\a^2c^2-a^2d^2+b^2c^2-b^2d^2\neq a^2c^2+b^2d^2-a^2d^2-b^2c^2$

D. True, because

$(a^2+b^2)(c^2+d^2)=a^2c^2+a^2d^2+b^2c^2+b^2d^2\\ \\(ac-bd)^2-(ad+bc)^2=a^2c^2-2abcd+b^2d^2+a^2d^2+2abcd+b^2c^2=\\=a^2c^2+b^2d^2+a^2d^2+b^2c^2\\ \\a^2c^2+a^2d^2+b^2c^2+b^2d^2= a^2c^2+b^2d^2+a^2d^2+b^2c^2$

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3 years ago