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arsen [322]
3 years ago
14

An object swings in a horizontal circle, supported by a 1.8-m string. It swings at a speed of 3 m/s. What is the mass of the obj

ect given that the tension in the string is 90 N?
Physics
1 answer:
Sidana [21]3 years ago
7 0

Answer:

Mass = 18 kg

Explanation:

Formula for force in centripetal motion is;

F = mv²/r

We have;

Mass; m.

Speed; v = 3 m/s

radius; r = 1.8 m

Force; F = 90 N

Thus;

Making m the subject;

m = Fr/v²

m = 90 × 1.8/3²

m = 18 kg

You might be interested in
1. What is the momentum of a 0.15 kg arrow that is traveling at 120 m/s?
Korvikt [17]

For this case we have that by definition, the momentum equation is given by:

p = m * v

Where:

m: It is the mass

v: It is the velocity

According to the data we have:

m = 0.15 \ kg\\v = 120 \frac {m} {s}

Substituting:

p = 0.15 * 120\\p = 18 \frac {kg * m} {s}

On the other hand, if we clear the variable "mass" we have:

m = \frac {p} {v}

According to the data we have:

p = 250 \frac {kg * m} {s}\\v = 5 \frac {m} {s}\\m = \frac {250} {5}\\m = 50 \ kg

Thus, the mass is 50 \ kg

Answer:

p = 18 \frac {kg * m} {s}\\m = 50 \ kg

3 0
3 years ago
A 40.0 turn coil of wire of radius 3.0 cm is placed between the poles of an electromagnet. The field increases from 0 to 0.75 T
nadezda [96]

Answer:

Induced emf, V=3.76\times 10^{-4}\ V

Explanation:

We have,

Number of turns in the coil, N = 40

Radius of coil, r = 3 cm = 0.03 m

The field increases from 0 to 0.75 T at a constant rate in a time interval of 225 s.

It is required to find the magnitude of the induced emf in the coil if the field is perpendicular to the plane of the coil. The induced emf is given by :

\epsilon=\dfrac{d\phi}{dt}

\phi=NBA\cos\theta, is magnetic flux

\epsilon=NA\dfrac{dB}{dt}\\\\\epsilon=\dfrac{40\times \pi (0.03)^2\times (0.75-0)}{225}\\\\\epsilon=3.76\times 10^{-4}\ V

So, the magnitude of induced emf is 3.76\times 10^{-4}\ V.

7 0
3 years ago
If a body of mass 10 kg is pushed with a force of 15N, then the acceleration of the body is
sladkih [1.3K]

Answer:

1.5m/s2

Explanation:

F=ma

a=F/m

a=15/10

a=1.5m/s2

7 0
3 years ago
How is a scientific explanation evaluated
Scrat [10]
You test it over and over again. so basically you experiment on it more. 
Hope this helps!
5 0
4 years ago
Read 2 more answers
What current flows through a 2.60-cm-diameter rod of pure silicon that is 20.5 cm long, when 1.00 ✕ 103 V is applied to it? (Suc
Virty [35]

Answer:

1.13 mA

Explanation:

Length of wire L = 20.5 cm = 0.205m

Radius of wire r = 2.60/2 = 1.3cm = 0.0130m

Voltage V = 1 × 10³ V

Resistivity of pure silicon p = 2300 Ohms • m

Cross sectional area of the wire

A = pi × r² = pi × (0.013)² = 5.307 × 10 ^-4 m²

Resistance of the material

R = p• L/A

= 2300 • 0.205/5.307 × 10^-4 = 0.888 × 10⁶ Ohms

Using Ohms Law

R = V/ I

I = V/R

I = 10³/0.888 × 10⁶

= 0.001126 A

= 1.13 mA

5 0
4 years ago
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