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Ahat [919]
3 years ago
9

1. A friend measures the length of the school

Physics
1 answer:
shusha [124]3 years ago
6 0

Answer:

option A

Explanation:

A soccer field is about 100 meters of length, with the other instruments is possible to make the measure, but it will be very complex and it will take time. Therefore with the 50-m tape, the student will need only two measures.

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Suppose that the resistance between the walls of a biological cell is 6.8 × 109 ω. (a) what is the current when the potential di
GenaCL600 [577]
(a) We can find the current flowing between the walls by using Ohm's law:
I= \frac{\Delta V}{R}
where \Delta V=69 mV=0.069 V is the potential difference and R=6.8\cdot 10^9 \Omega is the resistance. Substituting these values, we get
I=1.01 \cdot 10^{-11} A

(b) The total charge flowing between the walls is the product between the current and the time interval:
Q=I \Delta t
The problem says \Delta t=0.86 s, so the total charge is
Q=(1.01\cdot 10^{-11} A)(0.86 s)=8.73 \cdot 10^{-12} C

The current consists of Na+ ions, each of them having a charge of e=1.6 \cdot 10^{-19} C. To find the number of ions flowing, we can simply divide the total charge by the charge of a single ion:
N= \frac{Q}{e} = \frac{8.73 \cdot 10^{-12}C}{1.6 \cdot 10^{-19}C} = 5.45 \cdot 10^7 ions
4 0
3 years ago
Sound travels faster in ______ as compared to liquids.
FromTheMoon [43]

Answer:

Gases

Explanation:

5 0
2 years ago
Read 2 more answers
If earth increase the distance from the sun, what will happen to the period of orbi t(the time it takes to complete one revoluti
Mandarinka [93]

The period of the orbit would increase as well

Explanation:

We can answer this question by applying Kepler's third law, which states that:

"The square of the orbital period of a planet around the Sun is proportional to the cube of the semi-major axis of its orbit"

Mathematically,

\frac{T^2}{a^3}=const.

Where

T is the orbital period

a is the semi-major axis of the orbit

In this problem, the question asks what happens if the distance of the Earth from the Sun increases. Increasing this distance means increasing the semi-major axis of the orbit, a: but as we saw from the previous equation, the orbital period of the Earth is proportional to a, therefore as a increases, T increases as well.

Therefore, the period of the orbit would increase.

Learn more about Kepler's third law:

brainly.com/question/11168300

#LearnwithBrainly

5 0
3 years ago
) The square plates of a 5000-pF parallel-plate capacitor measure 50 mm by 50 mm and are separated by a dielectric that is 0.23
notsponge [240]

Answer:

4 x 10⁻⁴ J

Explanation:

C = 5000 pF, V = 400 V

Energy = CV²/2 = 5000 x 10⁻¹² x 400²/2 = 4 x 10⁻⁴ J

6 0
2 years ago
The massless spring of a spring gun has a force constant k=12~\text{N/cm}k=12 N/cm. When the gun is aimed vertically, a 15-g pro
ASHA 777 [7]

Answer:

0.011 m.

Explanation:

Energy stored in the spring = Energy of the projectile.

1/2ke² = mgh ................ Equation 1

Where k = spring constant, e = extension or compression, m = mass of the projectile, g = acceleration due to gravity, h = height.

make e the subject of the equation

e = √(2mgh/k)............................. Equation 2

Given: k = 12 N/cm = 1200 N/m, m = 15 g = 0.015 kg, h = 5.0 m

Constant: g = 9.8 m/s²

Substitute into equation 2

e = √(2×0.015×5/1200)

e = √(0.15/1200)

e = √(0.000125)

e = 0.011 m.

4 0
2 years ago
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