M = 30.3kg<br>M = 40.17kg 9<br>R = 0.5m<br>G = 6. 67x10^11<br>F ?

A diver wants to jump from a board, the initial height is 10 meters and he wants to reach a horizontal distance of 2 meters. Wha

bulgar [2K]

Answer:

1.4 m/s

Explanation:

The minimum speed will be when the diver's initial velocity is horizontal.

First, find the time it takes for the diver to fall 10 meters.

Given:

Δy = 10 m

v₀ᵧ = 0 m/s

aᵧ = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

10 m = (0 m/s) t + ½ (9.8 m/s²) t²

t = 1.43 s

Now find the initial horizontal velocity.

v = (2 m) / (1.43 s)

v = 1.4 m/s

4 0

3 years ago

The first car has twice the mass of a second car, but only half as much kinetic energy. When both cars increase their speed by 9

kirill [66]

Answer:

Speed of the car 1 = $V_1=8.98m/s$

Speed of the car 2 = $V_2=17.96m/s$

Explanation:

Given:

Mass of the car 1 , M₁ = Twice the mass of car 2(M₂)

mathematically,

M₁ = 2M₂

Kinetic Energy of the car 1 = Half the kinetic energy of the car 2

KE₁ = 0.5 KE₂

Now, the kinetic energy for a body is given as

$KE =\frac{1}{2}mv^2$

where,

m = mass of the body

v = velocity of the body

thus,

$\frac{1}{2}M_1V_1^2=0.5\times \frac{1}{2}M_2V_2^2$

or

$\frac{1}{2}2M_2V_1^2=0.5\times \frac{1}{2}M_2V_2^2$

or

$2M_2V_1^2=0.5\times M_2V_2^2$

or

$2V_1^2=0.5\times V_2^2$

or

$4V_1^2= V_2^2$

or

$2V_1= V_2$ .................(1)

also,

$\frac{1}{2}M_1(V_1+9.0)^2=\frac{1}{2}M_2(V_2+9.0)^2$

or

$\frac{1}{2}2M_2(V_1+9.0)^2=\frac{1}{2}M_2(2V_1+9.0)^2$

or

$2(V_1+9.0)^2=(2V_1+9.0)^2$

or

$\sqrt{2}(V_1+9.0)=(2V_1+9.0)$

or

$(\sqrt{2}V_1+ \sqrt{2}\times 9.0)=(2V_1+9.0)$

or

$(\sqrt{2}V_1+ 12.72)=(2V_1+9.0)$

or

$(2V_1-\sqrt{2}V_1)=(12.72-9.0)$

or

$(0.404V_1)=(3.72)$

or

$V_1=8.98m/s$

and, from equation (1)

$V_2=2\times 8.98m/s = 17.96m/s$

Hence,

Speed of car 1 = $V_1=8.98m/s$

Speed of car 2 = $V_2=17.96m/s$

8 0

3 years ago

Read 2 more answers

What Is Rotational Motion?

mars1129 [50]

Answer:

the motion of an object in a circular path , in a fixed orbit

8 0

3 years ago

Read 2 more answers

What is the most abundant type of sediment found on the ocean floor?

makvit [3.9K]

Its D that so easy look at it

4 0

3 years ago

What are the difficulties with the capture hypothesis of the Moon’s origin?

Lisa [10]

Answer:

No collision or altered trajectory

Similar percentage of oxygen isotopes

Explanation:

Capture hypothesis states that the Earth captured the moon. This is highly unlikely as such interactions of this type of bodies leads to a collision or their trajectories are altered. The percentage of the oxygen isotopes such as 16O, 17O and 18O in the Moon's basalts are almost identical with Earth. While meteorites have different percentage of oxygen isotopes.

Currently the accepted hypothesis is the giant-impact hypothesis.

5 0

3 years ago

M = 30.3kgM = 40.17kg 9R = 0.5mG = 6. 67x10^11F ?​

M = 30.3kgM = 40.17kg 9R = 0.5mG = 6. 67x10^11F ?