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Nata [24]
3 years ago
15

What is the prime factorization for 160 using exponents?

Mathematics
2 answers:
Fynjy0 [20]3 years ago
8 0
The prime factorization of 160 = 25•5.
bija089 [108]3 years ago
3 0

Answer:

2^5*5

Step-by-step explanation:

<u>Step 1:  Prime Factorization</u>

<u />160 → 2 * 2 * 2 * 2 * 2 * 5

2 * 2 * 2 * 2 * 2 * 5 → 2^5*5

Answer:  2^5*5

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A line that passes through the point (x,y), with a y-intercept of b and a slope of m, can be represented by the equation y = mx
tester [92]

Answer:

b=-18

Step-by-step explanation:

If a line that passes through the point P(x_o,y_o)and it has slope m, the equation of the line is:

y-y_o=m(x-x_o)~=>y=mx+y_o-mx_o~=>b=y_o-mx_o\\\\b=-6-4(3)=-18

4 0
2 years ago
F(x)=-3x+5x^2+8 has_____ roots
nikitadnepr [17]

Answer:12

Step-by-step explanation:

3 0
2 years ago
If anybody now this pls help my homework due TOMORROW
Nezavi [6.7K]

Answer:

<u><em>Part A:</em></u> D. y = (x + 1)(x+3)\\

<u><em>Part B:</em></u> C. 3x(x-3) = 0\\

Step-by-step explanation:

For part A) we just have to plug in 0 for x and solve for y until we find the equation that says 3 is the value for y when x is 0. For purposes of speeding up the process the correct answer is D. I will show how to check for it now.

The equation: y = (x + 1)(x+3)

Now plug in 0 for x.

y = (0 + 1)(0+3)\\

Now solve.

y = (1)(3)

y = 3

This proves that this is the correct answer.

For part B) we just have to plug in the give values for x separately and check for each value of x that it equals 0. For the purpose of speeding up the process the correct answer is C. I will show how to check for it now.

The equation: 3x(x-3) = 0

Now plug in x for 0 and solve:

3* 0 (0-3) = 0\\

0(-3) = 0\\

0 =0\\

This equation is true, now we check for the other value of x, 3.

3*3(3-3) = 0\\

9(0) = 0\\

0 =0\\

This is also true so that means this is the correct answer.

6 0
3 years ago
Can you show me the steps to factor out 8x^3 - 27y^3?
Travka [436]

(2x-3y)(4x^2+6xy+9y^2) is the factored form of 8x^3-27y^3

<em><u>Solution:</u></em>

We have to factor the given expression

8x^3-27y^3

We can use the algebraic identity to factor the given expression

a^3-b^3=(a-b)(a^2+ab+b^2)

Lets make the given expression in form of a^3-b^3

8x^3-27y^3=(2)^3(x)^3-(3)^3(y)^3

8x^3-27y^3=(2x)^3-(3y)^3

Now apply the algebraic property in above expression

Here, a = 2x and b = 3y

Therefore,

(2x)^3-(3y)^3=(2x-3y)((2x)^2+(2x)(3y)+(3y)^2)

(2x)^3-(3y)^3=(2x-3y)(4x^2+6xy+9y^2)

Thus the given expression is factored out

7 0
3 years ago
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