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erastova [34]
3 years ago
12

A random variable X follows a Binomial distribution; i.E. X ~ B(12, p) with a variance of 1.92. Compute the possible values of p

Mathematics
1 answer:
frutty [35]3 years ago
4 0
<h3>2 Answers:   p = 0.2 and p = 0.8</h3>

==================================================

Explanation:

Any binomial distribution has two unique components to it: The number of trials n, and the probability of success p.

We're given n = 12, and we need to find p.

The variance of a binomial probability distribution is given by the formula n*p*(1-p). Plug in n = 12 and set this equal to 1.92

So the equation to solve is 12p*(1-p) = 1.92

Solve for p using a graphing calculator or you could apply the quadratic formula. Either way, you should get the two results of p = 0.2 and p = 0.8

Note that if p = 0.2, then 1-p = 1-0.2 = 0.8, and things flip around when p = 0.8.

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(5x+2) = 32 what is the value of x ?
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Answer:

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Step-by-step explanation:

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Will mark as brainliest
oksano4ka [1.4K]

Answer:

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Step-by-step explanation:

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it should be |-1| = |1|

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4 0
3 years ago
I need to know how to do Solving Systems of Equations by Elimination
vredina [299]
The point of elimination is to have one variable so example

3x + 2y = 4

7X + 3y = 5


1) Try to find a way to have one variable

7(3x + 2y = 4) ----> 21x + 14y = 28

-3(7x+ 3y = 5) -----> -21x -9y = -15


2) add

0 + 5y = 13

3) solve for the last variable

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4) Subsitute the variable to get the other one

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x = 0.533333333 (continue)

The intersection would be 0.53 with a line above the 3 and 2.8. (0.5333 , 2.8)

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3 years ago
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