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IgorLugansk [536]
3 years ago
6

Solve 9x-10÷2=x+9explain how​

Mathematics
1 answer:
Mariulka [41]3 years ago
7 0

Answer:

x = 4

Step-by-step explanation:

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Find the common difference of the arithmetic sequence -3, -9, -15
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2 years ago
A conical container can hold 120π cubic centimeters of water. The diameter of the base of the container is 12 centimeters.
Tanzania [10]

Answer: The height of the container is 10 centimeters. If its diameter and height were both doubled, the container's capacity would be 8 times its original capacity.

Step-by-step explanation:

The volume of a cone can be calculated with this formula:

V=\frac{\pi r^2h}{3}

Where "r" is the radius and "h" is the height.

We know that the radius is half the diameter. Then:

r=\frac{12cm}{2}=6cm

We know the volume and the radius of the conical container, then we can find "h":

120\pi cm^3=\frac{\pi (6cm)^2h}{3}\\\\(3)(120\pi cm^3)=\pi (6cm)^2h\\\\h=\frac{3(120\pi cm^3)}{\pi (6cm)^2}\\\\h=10cm

The diameter and height doubled are:

d=12cm*2=24cm\\h=10cm*2=20cm

Now the radius is:

r=\frac{24cm}{2}=12cm

And the container capacity is

V=\frac{\pi (12cm)^2(20cm)}{3}=960\pi cm^3

Then, to compare the capacities, we can divide this new capacity by the original:

 \frac{960\pi cm^3}{120\pi cm^3}=8

Therefore,  the container's capacity would be 8 times its original capacity.

6 0
2 years ago
Read 2 more answers
The population of Henderson City was 3,381,000 in 1994, and is growing at an annual rate 1.8%
liq [111]
<h2>In the year 2000, population will be 3,762,979 approximately. Population will double by the year 2033.</h2>

Step-by-step explanation:

   Given that the population grows every year at the same rate( 1.8% ), we can model the population similar to a compound Interest problem.

   From 1994, every subsequent year the new population is obtained by multiplying the previous years' population by \frac{100+1.8}{100} = \frac{101.8}{100}.

   So, the population in the year t can be given by P(t)=3,381,000\textrm{x}(\frac{101.8}{100})^{(t-1994)}

   Population in the year 2000 = 3,381,000\textrm{x}(\frac{101.8}{100})^{6}=3,762,979.38

Population in year 2000 = 3,762,979

   Let us assume population doubles by year y.

2\textrm{x}(3,381,000)=(3,381,000)\textrm{x}(\frac{101.8}{100})^{(y-1994)}

log_{10}2=(y-1994)log_{10}(\frac{101.8}{100})

y-1994=\frac{log_{10}2}{log_{10}1.018}=38.8537

y≈2033

∴ By 2033, the population doubles.

4 0
3 years ago
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