Substitute
, so that

Then the resulting ODE in
is separable, with

On the left, we can split into partial fractions:

Integrating both sides gives




Now solve for
:


You just have to divide the 1/2 a pound by 8, or equivalently multiply by (1/8):
(1/2)*(1/8) = 1/16 of a pound
The correct answer is
the flagpole is <span>
33 feet high</span>.
Explanation:
Please refer to the attached picture.
We know:
CD = 40 feet
AC = 5 feet
∠BDC = α = 35°
Using trigonometry, we know that the definition of the tangent of an angle is the ratio between the opposite side and the adjacent side, therefore:
tan α = BC / CD
Solving for BC:
BC = CD · <span>tan α
= 40 </span>· tan (35)
= 28 feet
In order to find the height of the flagpole, we need to add the distance of the clinometer from the ground:
AB = BC + AC
= 28 + 5
= 33
Hence, the flagpole is
33 feet high.
Answers:
x = 6
y = 6*sqrt(2)
=======================
Explanation:
To find these values, you can use the general template of a 45-45-90 triangle or you can use trig ratios
tan(45) = 1
tan(angle) = opposite/adjacent
tan(45) = x/6
1 = x/6
6*1 = x
x = 6
-------
sin(45) = 1/sqrt(2)
sin(angle) = opposite/hypotenuse
sin(45) = 6/y
1/sqrt(2) = 6/y
1*y = sqrt(2)*6
y = 6*sqrt(2)