Answer:
a) P=0.03
b) α=0.05
c) 0.72
d) 100
e) 0.72
Step-by-step explanation:
a) The P-value is the probability of the sample result. In this case the P-value is 0.03.
b) The level of significance is the threshold of probabilty for the null hypothesis to be reejcted or not. It is contrasted with the P-value to know if the effect is significant. In this case, the level of significance is 0.05.
NOTE: if it is a two-side test, the level of significance is 0.1 (two times 0.05).
c) The sample proportion is the one that results from the sample data. In this case, the sample proportion is 0.72.
d) The sample size is the amount of consumers reported. In this case is 100 customers.
e) The null value is 0.72 (equal to the sample proportion), because it is tested if there is no difference between the population proportion and the sample proportion.
PEMDAS is an acronym that refers to the sequence of operations to be employed when solving equations with multiple operations. The solution of the given expression (2×2)² - [3+(2×2)]/(6-4) is 14.
<h3>What is PEMDAS?</h3>
PEMDAS is an acronym that refers to the sequence of operations to be employed when solving equations with multiple operations. PEMDAS is an acronym that stands for P-Parenthesis, E-Exponents, M-Multiplication, D-Division, A-Addition, and S-Subtraction.
As per the rule of PEMDAS, the given expression can be simplified as shown below.
(2×2)² - [3+(2×2)]/(6-4)
Step 1: Solving Parenthesis,
= 4² - (3+4) / (2)
= 4² - 4/2
Step 2: Solving exponents,
= 16 - 4/2
Step 3: Solving Divisions,
= 16 - 2
Step 4: Solving Subtraction,
= 14
Hence, the solution of the given expression (2×2)² - [3+(2×2)]/(6-4) is 14.
Learn more about PEMDAS here:
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Answer:
see explaination
Step-by-step explanation:
Using the formulla that
sum of terms number of terms sample mean -
Gives the sample mean as \mu=17.954
Now varaince is given by
s^2=\frac{1}{50-1}\sum_{i=1}^{49}(x_i-19.954)^2=9.97
and the standard deviation is s=\sqrt{9.97}=3.16
b) The standard error is given by
\frac{s}{\sqrt{n-1}}=\frac{3.16}{\sqrt{49}}=0.45
c) For the given data we have the least number in the sample is 12.0 and the greatest number in the sample is 24.1
Q_1=15.83, \mathrm{Median}=17.55 and Q_3=19.88
d) Since the interquartile range is Q_3-Q_1=19.88-15.83=4.05
Now the outlier is a number which is greater than 19.88+1.5(4.05)=25.96
or a number which is less than 15.83-1.5(4.05)=9.76
As there is no such number so the given sample has no outliers
Answer:
Step-by-step explanation:
I don't think this can be done without the diagram. You do not know what HD is opposite. I will take a guess that it is opposite TU which makes TU = 220 because both H and D are midpoints and that makes TU twice as large as HD.
If this is incorrect, post the diagram.
