Ask question

Ask question

All categories

3 years ago

11

Describe in words how to find the surface area of a cylinder if the radius is 5cm and height is 18cm. The formula is =+.Once you

are finished, explain what you would change if it was an open cylinder or a "cup".

1 answer:

nordsb [41]3 years ago

3 0

Surface area of cylinder is 2(pi)r^2 + 2(pi)rh
r=5cm
h=18cm
*fill in
50pi + 180pi = 230pi

You might be interested in

Determine the values of A,B, and C when y-7=3(x+4)

Alja [10]

Answer:

y= 3x + 19, x E R

Step-by-step explanation:

y - 7 = 3 (x + 4)

(distribute the 3 through the parentheses)

y= 3x + 12 + 7

(add the numbers)

y = 3x + 19

(write the solution/answer Y in parametric form)

y = 3x + 19, x E R

3 0

3 years ago

It cost 0.17 to mail a postcard and 0.25 to mail a letter. If Dykov spent $4.35 and wrote postcards and letters to 19 friends, h

guapka [62]

Answer:

14 Letters and 5 Postcards

Step-by-step explanation:

3 0

3 years ago

Which shape will result from taking a cross section of the tetrahedron through the points shown?

Svetach [21]

Answer:

the anwer is a triangle as it is shown below.

5 0

2 years ago

Which of the following illustrates the truth value of the given statements? January is the first month of the year or December i

Dafna11 [192]

First, the need to determine if the statements are true or false.

1) January is the first month of the year. (This statement is true)
2) December is the last month of the year. (This statement is also true)

With this in mind we can determine that what will illustrate the truth value would be:

T T -> T

In other words, since the first statement is true and the second statement is also true then conjunction of both statements would be true.

5 0

3 years ago

Read 2 more answers

Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

7 0

3 years ago