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shtirl [24]
2 years ago
9

A chocolate chip cookie recipe needs 2 cups of chocolate chips and teaspoon of salt. If the recipe is increased to 6 cups of cho

colate
chips, how many teaspoons of salt are needed?
Mathematics
1 answer:
olasank [31]2 years ago
5 0

Answer:

3 teaspoons

Step-by-step explanation:

Since we need 1 teaspoon for 2 cups, I would only assume we would keep adding a teaspoon for every 2 additional cups of chocolate chips.

2 + 2 + 2 = 6

We would need an additional teaspoon of salt for each of the sets of two.

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Nostrana [21]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Find the height of the trapezoid. A trapezoid. The base lengths are 10 meters and 6 meters. The area is 40 square meters.
Andrew [12]

Answer:

5 meters

Step-by-step explanation:

A=a+b/2*h

40=10+6/2*h

40=8h

h=5

7 0
3 years ago
Read 2 more answers
If point C (3, 8) is reflected over the y axis what would be point C'?<br>no links please ​
olga2289 [7]

Answer:

(-3,8)

Step-by-step explanation:

When reflecting over the y-axis, you are switching from positive to negative x-values. Since 3 was already positive, we change the integer and in this case, to negative, so it becomes -3. Since the y value remains the same we don’t change the 8. So (-3,8)

I hope this helps!

Please give thanks or brainliest if this helps!

8 0
2 years ago
Read 2 more answers
Will mark brainliest for the correct answer!
romanna [79]

Part (a)

Focus on triangle PSQ. We have

angle P = 52

side PQ = 6.8

side SQ = 5.4

Use of the law of sines to determine angle S

sin(S)/PQ = sin(P)/SQ

sin(S)/(6.8) = sin(52)/(5.4)

sin(S) = 6.8*sin(52)/(5.4)

sin(S) = 0.99230983787513

S = arcsin(0.99230983787513)

S = 82.889762826274

Which is approximate

------------

Use this to find angle Q. Again we're only focusing on triangle PSQ.

P+S+Q = 180

Q = 180-P-S

Q = 180-52-82.889762826274

Q = 45.110237173726

Which is also approximate.

A more specific name for this angle is angle PQS, which will be useful later in part (b).

------------

Now find the area of triangle PSQ

area of triangle = 0.5*(side1)*(side2)*sin(included angle)

area of triangle PSQ = 0.5*(PQ)*(SQ)*sin(angle Q)

area of triangle PSQ = 0.5*(6.8)*(5.4)*sin(45.110237173726)

area of triangle PSQ = 13.0074347717966

------------

Next we'll use the fact that RS:SP is 2:1.

This means RS is twice as long as SP. Consequently, this means the area of triangle RSQ is twice that of the area of triangle PSQ. It might help to rotate the diagram so that line PSR is horizontal and Q is above this horizontal line.

We found

area of triangle PSQ = 13.0074347717966

So,

area of triangle RSQ = 2*(area of triangle PSQ)

area of triangle RSQ = 2*13.0074347717966

area of triangle RSQ = 26.0148695435932

------------

We're onto the last step. Add up the smaller triangular areas we found

area of triangle PQR = (area of triangle PSQ)+(area of triangle RSQ)

area of triangle PQR = (13.0074347717966)+(26.0148695435932)

area of triangle PQR = 39.0223043153899

------------

<h3>Answer: 39.0223043153899</h3>

This value is approximate. Round however you need to.

===========================================

Part (b)

Focus on triangle PSQ. Let's find the length of PS.

We'll use the value of angle Q to determine this length.

We'll use the law of sines

sin(Q)/(PS) = sin(P)/(SQ)

sin(45.110237173726)/(PS) = sin(52)/(5.4)

5.4*sin(45.110237173726) = PS*sin(52)

PS = 5.4*sin(45.110237173726)/sin(52)

PS = 4.8549034284642

Because RS is twice as long as PS, we know that

RS = 2*PS = 2*4.8549034284642 = 9.7098068569284

So,

PR = RS+PS

PR = 9.7098068569284 + 4.8549034284642

PR = 14.5647102853927

-------------

Next we use the law of cosines to find RQ

Focus on triangle PQR

c^2 = a^2 + b^2 - 2ab*cos(C)

(RQ)^2 = (PR)^2 + (PQ)^2 - 2(PR)*(PQ)*cos(P)

(RQ)^2 = (14.5647102853927)^2 + (6.8)^2 - 2(14.5647102853927)*(6.8)*cos(52)

(RQ)^2 = 136.420523798282

RQ = sqrt(136.420523798282)

RQ = 11.6799196828694

--------------

We'll use the law of sines to find angle R of triangle PQR

sin(R)/PQ = sin(P)/RQ

sin(R)/6.8 = sin(52)/11.6799196828694

sin(R) = 6.8*sin(52)/11.6799196828694

sin(R) = 0.4587765387107

R = arcsin(0.4587765387107)

R = 27.3081879220073

--------------

This leads to

P+Q+R = 180

Q = 180-P-R

Q = 180-52-27.3081879220073

Q = 100.691812077992

This is the measure of angle PQR

subtract off angle PQS found back in part (a)

angle SQR = (anglePQR) - (anglePQS)

angle SQR = (100.691812077992) - (45.110237173726)

angle SQR = 55.581574904266

--------------

<h3>Answer: 55.581574904266</h3>

This value is approximate. Round however you need to.

8 0
3 years ago
if the measure of &lt;BEC is (2x+3)° and x=30, which expression could represent the measure of &lt;AED?​
Maurinko [17]

Answer:

The answer is 3x-27

Step-by-step explanation:

If the angles are vertical from each other it means they are congruent. 2x+30 is 63, you plug in the x, 2(30)+30. You do that to the second one and also get 63, 3(30)-27. Therefore 3x-21 is the answer.

8 0
3 years ago
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