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3 years ago

Y = -x - 2 | what is the slope and y-intercept?

Mathematics

2 answers:

riadik2000 [5.3K]3 years ago

5 0

slope is -1

y-int is -2

its in y=mx+b form

b is the int

m is the slope

KIM [24]3 years ago

3 0

Remember from now on ,

The coefficient of x in slope-intercept form ( y = ax + b ) of the linear equations, is the slope of the line.

Thus : y = -1 ×( x ) - 2

The coefficient of x in the above function is - 1 so the slope of the above function is - 1 .

_________________________________

To find the y-intercept of any equations we have to put 0 instead of x in the equation and solve the equation to find the value of y which is the y-intercept of our equation.

y = - x - 2

put 0 instead of x

y = - 0 - 2

y = - 2

Thus the y-intercept is - 2 .

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FrozenT [24]

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The angle formed by the person and the tree with the ground = Right angles = 90°

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The height of the person, h₁ = 6 ft.

The distance of the tree from the mirror, d₂ = 12 ft.

The angle formed by the incident light from the tree on the mirror, θ₁ = The angle of the reflected light from the mirror to the person, θ₂

Let 'A', 'B', 'M', 'T', and 'R' represent the location of the point at the top of the person's head, the location of the point at the person's feet, the location of the mirror, the location of the top of the tree and the location of the root collar of the tree, we have;

TR in ΔMRT = The height of the tree = h, and right triangles ΔABM and ΔMRT are similar

The corresponding legs are;

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Given that θ₁ = θ₂, we have;

tan(θ₁) = tan(θ₂)

∴ tan(∠TMR) = tan(∠AMB)

$tan\angle X = \dfrac{Opposite \ leg \ length \ to \ reference \ angle}{Adjacent \ leg \ length \ to \ reference \ angle}$

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From tan(∠TMR) = tan(∠AMB), we have;

$\dfrac{h}{12} = \dfrac{6}{5}$

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Therefore, from the proportion $\dfrac{h}{12} = \dfrac{6}{5}$ the height of the tree can be estimated.

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