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2 years ago

6

A vase in the shape of a cube measures 8 inches on each side. The vase is half full of water. How many cubic inches of water are

in the vase?

1 answer:

Ne4ueva [31]2 years ago

7 0

Answer:

256

Step-by-step explanation:

First find the volume of the cube, which is 8^3, or 512. Half of that is how much water there is, which is 256 in^3.

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help I literally got a 4/10 in my math test and my mom is like REALLLLY mad that she took my phone so I’m using my sisters ipad

Aloiza [94]

Answer:

3/8 < 2/4

2/3 > 7/12

i could be wrong sorry

4 0

2 years ago

Read 2 more answers

Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro

Ugo [173]

Answer:

$Side\ B = 6.0$

$\alpha = 56.3$

$\theta = 93.7$

Step-by-step explanation:

Given

Let the three sides be represented with A, B, C

Let the angles be represented with $\alpha, \beta, \theta$

[See Attachment for Triangle]

$A = 10cm$

$C = 12cm$

$\beta = 30$

What the question is to calculate the third length (Side B) and the other 2 angles ( $\alpha\ and\ \theta$ )

Solving for Side B;

When two angles of a triangle are known, the third side is calculated as thus;

$B^2 = A^2 + C^2 - 2ABCos\beta$

Substitute: $A = 10$ , $C =12$ ; $\beta = 30$

$B^2 = 10^2 + 12^2 - 2 * 10 * 12 *Cos30$

$B^2 = 100 + 144 - 240*0.86602540378$

$B^2 = 100 + 144 - 207.846096907$

$B^2 = 36.153903093$

Take Square root of both sides

$\sqrt{B^2} = \sqrt{36.153903093}$

$B = \sqrt{36.153903093}$

$B = 6.0128115797$

$B = 6.0$ <em>(Approximated)</em>

Calculating Angle $\alpha$

$A^2 = B^2 + C^2 - 2BCCos\alpha$

Substitute: $A = 10$ , $C =12$ ; $B = 6$

$10^2 = 6^2 + 12^2 - 2 * 6 * 12 *Cos\alpha$

$100 = 36 + 144 - 144 *Cos\alpha$

$100 = 36 + 144 - 144 *Cos\alpha$

$100 = 180 - 144 *Cos\alpha$

Subtract 180 from both sides

$100 - 180 = 180 - 180 - 144 *Cos\alpha$

$-80 = - 144 *Cos\alpha$

Divide both sides by -144

$\frac{-80}{-144} = \frac{- 144 *Cos\alpha}{-144}$

$\frac{-80}{-144} = Cos\alpha$

$0.5555556 = Cos\alpha$

Take arccos of both sides

$Cos^{-1}(0.5555556) = Cos^{-1}(Cos\alpha)$

$Cos^{-1}(0.5555556) = \alpha$

$56.25098078 = \alpha$

$\alpha = 56.3$ <em>(Approximated)</em>

Calculating $\theta$

Sum of angles in a triangle = 180

Hence;

$\alpha + \beta + \theta = 180$

$30 + 56.3 + \theta = 180$

$86.3 + \theta = 180$

Make $\theta$ the subject of formula

$\theta = 180 - 86.3$

$\theta = 93.7$

5 0

2 years ago

What multiples for 90 and adds up to -23 ?

melamori03 [73]

Easy buddy...

_________________________________

Step (1)

I choose a number which is x

_________________________________

Step (2)

Multiplies by 90 :

$90x$

_________________________________

Step (3)

Adds up to -23 :

$90x - 23$

_________________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

7 0

2 years ago

Pls help me answer the question and if you don't know, pls don't answer. thank you!

Damm [24]

The answer is 162in2 to its orbit

6 0

2 years ago

The total cost of an order of gift baskets includes the cost of each gift basket plus a one time delivery fee. The cost of each

Helen [10]

Answer:

x = cost of each gift basket = $14.5

y = one time delivery fee = $135

Step-by-step explanation:

Let

x = cost of each gift basket

y = one time delivery fee

40x + y = 715 (1)

400x + y = 5935 (2)

Subtract (1) from (2)

400x - 40x = 5935 - 715

360x = 5220

x = 5220/360

x = 14.5

Substitute x = 14.5 into (1)

40x + y = 715 (1)

40(14.5) + y = 715

580 + y = 715

y = 715 - 580

y = 135

x = cost of each gift basket = $14.5

y = one time delivery fee = $135

4 0

2 years ago