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julsineya [31]
3 years ago
5

A load of bricks is twice as heavy as a load of sticks. The total weight of 4 loads of bricks and 4 loads of sticks is 771 kilog

rams. What is the total weight of 1 load of bricks and 3 loads of sticks? I need help answering.. I don't understand . Do I divide 4 into 771 and then divide 3 into 771?
Mathematics
1 answer:
Kryger [21]3 years ago
6 0
You have to divide the 4
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6. A coupon offers $1.00 off the 16-ounce size. Which size is the better<br><br> buy then?
svlad2 [7]

Answer:

Both sizes are better because they cost Same.

Step-by-step explanation:

Consider the provided information.

A coupon offers $1.00 off the 16

            Quantity     Price

Pint           16           $3.98

Quart        32           $5.98

If he gets $1 off for the 16-ounce size. The price will be:

3.98-1=2.98

He needs to pay $2.98 for 16-ounce pint.

Now find which one is better by calculating the unit rate.

\frac{Cost}{weight}=\frac{2.98 }{16}\approx0.186

Therefore, the cost of 1lb would be $0.186

For Quart 32 find the unit rate as shown:

\frac{Cost}{weight}=\frac{5.98}{32}\approx0.186

Therefore, the cost of 1lb would be $0.186

Hence, both of the size are better as the unit rate is same.

4 0
3 years ago
The product of a number w and 737
Nimfa-mama [501]
The product (multiplication) of a number w and 737.

737w
7 0
3 years ago
Eight less than the product of 3 and a number is 7
Levart [38]
Perhaps you want to know what the number is?

3n -8 = 7
3n = 15 . . . . . add 8
n = 5 . . . . . . . divide by 3

The number is 5.
4 0
3 years ago
The weight of an object on mars varies directly is proportional as the weight of the object on earth a 75 pound object on earth
dedylja [7]

Answer:

It weighs 40 pounds on mars

Step-by-step explanation:

Direct proportion is the relationship between two variables when their ratio is equal to a constant value

  • It can be expressed as y = k x, where y varies directly as x and k is constant of variation
  • It can be expressed as  \frac{y_{1}}{x_{1}}=\frac{y_{2}}{x_{2}}=k

∵ The weight of an object on mars varies directly as the weight

    of the object on earth

∴ w(m) = k × w(e)

∵ The weight of the object on earth is 75 pound

∴ w(e) = 75

∵ The weight of this object on mars is 25 pounds

∴ w(m) = 25

- Substitute them in the equation of variation

∵ 25 = k × 75

- Divide both sides by 75

∴ \frac{1}{3} = k

∴ w(m) = \frac{1}{3} × w(e)

∵ An object weighs 120 pounds on earth

∴ w(e) = 120

- Substitute it in the equation of variation

∴ w(m) = \frac{1}{3} × 120

∴ w(m) = 40

∴ It weighs 40 pounds on mars

5 0
3 years ago
Paul jogged for 2/10 of an hour. Ones jogged for 5/8 of an hour. Who jogged for a longer period of time? How much longer?
AleksandrR [38]
Ones jogged for a longer period of time.
by 17/40
6 0
3 years ago
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