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3 years ago

Factor completely. 27x^3-12x

Mathematics

2 answers:

grandymaker [24]3 years ago

6 0

You will have to take 3x common from both terms and your ans should look like this,
3x(9x^2-4)

forsale [732]3 years ago

4 0

$27x^3-12x \\ =3x\times9x-3x\times4 \\ =3x(9x-4)$

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Valentin [98]

I think its... A (but not sure)

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3 years ago

Please help asap!!!

Tatiana [17]

Answer:

$w = 6$

Step-by-step explanation:

ST = w + 6,

PR = w

From the diagram given, we can deduce that PR is the midsegment of ∆QST. Therefore, according to the midsegment theorem:

PR = ½ of ST

Plug in the values into the equation and solve for w.

$w = \frac{1}{2}(w + 6)$

$w = \frac{w}{2} + 3$ (distributive property of equality)

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$2(w - 3) = \frac{w}{2}*2$ (multiplication property of equality)

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5 0

3 years ago

This is an Accounting Question, but there's no subject for it!

kykrilka [37]

it is correct

Step-by-step explanation:

6 0

3 years ago

5 Michiko has a metal container in the shape of a cuboid. The container is 2.4 m long, 1.2 m wide and 0.6 m high. Michiko plans

konstantin123 [22]

Answer:

a) Michiko needs to buy 18 tins of paint.

b) cost of paint would be $152.82

Step-by-step explanation:

Surface area of cuboid = 2lw + 2lh + 2hw

Length (l) = 2.4 m

Width (w) = 1.2 m

Height (h) = 0.6 m

SF = 2(2.4 × 1.2) + 2(2.4 × 0.6) + 2(0.6 × 1.2)

= 5.76 + 2.88 + 1.44

= 10.08 meter²

Paint coverage is 4.5 meter² per liter.

Total paint used in one coat =

= 2.24 liters

Paint used in double coats = 2.24 × 2 = 4.48 liters

a) Size of one tin paint = 250 ml

1 liters = 1000 ml

4.48 liters = 4.48 × 1000 = 4480 ml

Number of tins needed by Michiko =

= 17.92 ≈ 18 tins

b) Cost of one tin of metal paint = $8.49

∴ cost of 18 tins of paint = $152.82

a) Michiko needs to buy 18 tins of paint.

b) cost of paint would be $152.82

3 0

2 years ago

A slide 15 feet long makes an angle of 330 with its vertical ladder. To the

Shkiper50 [21]

Answer:

13ft

Step-by-step explanation:

Kindly find attached a rough draft of the situation.

Step one:

Given data

The length of the slide represents the

Hypotenuse of the situation on the rough sketch

Angle =33°

Required

The height of the ladder which is the adjacent of the rough sketch represented by x

Step two:

Applying SOH CAH TOA

Cos θ= adj/hyp

Cos 33=x/15

0.84=x/15

Cross multiplying

x=0.84*15

x=12.6

To the nearest foot the ladder is 13ft tall

6 0

2 years ago