All categories

3 years ago

5x + 2y = -10 Graph the equation

Mathematics

1 answer:

mars1129 [50]3 years ago

7 0

Answer:

Desmos graphing calculator is a very helpful tool!

5x+2y=10

Step-by-step explanation:

You might be interested in

Which equation can be used to solve the following word problem? Seth has 8 more nickels than dimes, and the total value of his c

9966 [12]

Answer:

Seth has 21 nickels

Step-by-step explanation:

Let n represent the number of nickels. Since Seth has 8 more nickels than dimes, then (n-8) is the number dimes.

Nickel is worth 5 cents and dime is worth 10 cents. Thus, n nickels are worth 5n cents and (n-8) dimes are worth 10(n-8) cents. The total value of Seth's coins is $2.35 that is 235 cents, then

$5n+10(n-8)=235.$

Solve this equation:

$5n+10n-80=235,\\ \\15n=235+80,\\ \\15n=315,\\ \\n=21.$

6 0

3 years ago

The expected number of typographical errors on a page of a certain magazine is .2. What is the probability that an article of 10

Pavel [41]

Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

$N\sim Pois(0.2)$

$P(N=r)=\frac{e^{-np}(np)^r}{r!}$

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

$P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}$

$P(N=0)=\frac{e^{-0.2}}{1}$

$P(N=0)=e^{-0.2}$

$P(N=0)=0.8187$

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute $r\geq 2$ in formula,

$P(N\geq 2)=1-P(N$

$P(N\geq 2)=1-[P(N=0)+P(N=1)]$

$P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]$

$P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]$

$P(N\geq 2)=1-[0.8187+0.1637]$

$P(N\geq 2)=1-0.9825$

$P(N\geq 2)=0.0175$

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

6 0

3 years ago

A washer and a dryer cost $744 combined, the washer costs $94 more than the dryer, what is the cost of the dryer?

sp2606 [1]

Answer: 325$

Explanation:
Assume: A is the cost of washer
And B is the cost of dryer

A+B = 744
And: A = B + 94$
We get:

B + 94$ + B = 744
2B + 94 = 744
2B = 650
B = 325

3 0

3 years ago

Read 2 more answers

Evaluate a - b + c for a = 4 1/5,b =2 7/20, and c= 3 1/4

gavmur [86]

Answer:

5 1/4

Step-by-step explanation:

4 1/5 - 2 7/20 + 3 1/4

Common denominator = 20.

4 4/20 - 2 7/20 + 3 5/20

7 12/20 - 2 7/20 = 5 5/20 = 5 1/4