Calculate the difference between the two times.<br> 8: 15 am. or pm <br><br> 3: 30 am or pm.

Identify the center<br> (x + 9)^2+ y^2= 64

Mashcka [7]

Your Center is : (-9,0).

8 0

2 years ago

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Write the equation of circle b with center B(-2,3) that passes through (1,2)

professor190 [17]

Answer:

$(x+2)^2 + (y-3)^2 = 10$

Step-by-step explanation:

The standard equation for circle is

$(x-a)^2 + (y-b)^2 = r^2$

where point (a,b) is coordinate of center of circle and r is the radius.

______________________________________________________

Given

center of circle =((-2,3)

let r be the radius of circle

Plugging in this value of center in standard equation for circle given above we have

$(x-a)^2 + (y-b)^2 = r^2 \ substitute (a,b) \ with (-2,3) \\=>(x-(-2))^2 + (y-3)^2 = r^2 \\=>(x+2)^2 + (y-3)^2 = r^2 (1)$

Given that point (1,2 ) passes through circle. Hence this point will satisfy the above equation of circle.

Plugging in the point (1,2 ) in equation 1 we have

$\\=>(x+2)^2 + (y-3)^2 = r^2 \\=> (1+2)^2 + (2-3)^2 = r^2\\=> 3^2 + (-1)^2 = r^2\\=> 9 + 1 = r^2\\=> 10 = r^2\\=> r^2 = 10\\$

now we have value of r^2 = 10, substituting this in equation 1 we have

Thus complete equation of circle is $=>(x+2)^2 + (y-3)^2 = r^2\\=>(x+2)^2 + (y-3)^2 = 10$

7 0

3 years ago

The weights of newborn baby boys born at a local hospital are believed to have a normal distribution with a mean weight of 4016

hodyreva [135]

Answer:

Required Probability = 0.97062

Step-by-step explanation:

We are given that the weights of newborn baby boys born at a local hospital are believed to have a normal distribution with a mean weight of 4016 grams and a standard deviation of 532 grams.

Let X = weight of the newborn baby, so X ~ N( $\mu=4016 , \sigma^{2} = 532^{2}$ )

The standard normal z distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

Now, probability that the weight will be less than 5026 grams = P(X < 5026)

P(X < 5026) = P( $\frac{X-\mu}{\sigma}$ < $\frac{5026-4016}{532}$ ) = P(Z < 1.89) = 0.97062

Therefore, the probability that the weight will be less than 5026 grams is 0.97062 .

5 0

3 years ago

Property in Live Oak County is assessed at $250,000,000. The taxes to be raised are $10,000,000. What is the tax rate?

vekshin1

4% on the taxes. 10mil/ 250 mil = .04

4 0

3 years ago

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The number of text messsages that teenagers send per month is normally

ki77a [65]

Answer:

$z=\frac{4415-3400}{450}=2.26$

And the explanation of this number is:"The number of text messages for Kendra it's 2.26 deviations above the mean"

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

2) Calculate the z score

Let X the random variable that represent the number of text messages per month, and for this case we know the distribution for X is given by:

$X \sim N(3400,450)$