If a car travels 80 km/total distance is 450 km, how much time is required to reach? A car covers half of the distance between two places at 40km per hour and the other half distance at 60 km per hour!
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Answer:
w = -3
Step-by-step explanation:
-4w - 4 = 8
Combine the constants by adding 4 to both sides.
-4w = 12
Isolate w by dividing by -4.
w = -3
Check your work by plugging w = -3 into the original equation.
-4(-3) - 4 = 8
12 - 4 = 8
8 = 8
Your answer is correct.
Answer:
60%
Step-by-step explanation:
There are a total of 45 people 24 boys and 21 girl=45
27 of them are in the club 27 out of 45=60%
Answer:
Area of ΔDEF is
.
Step-by-step explanation:
Given;
ΔABC and ΔDEF is similar and ∠B ≅ ∠E.
Length of AB =
and
Length of DE = ![6\ cm](https://tex.z-dn.net/?f=6%5C%20cm)
Area of ΔABC = ![5\ cm^2](https://tex.z-dn.net/?f=5%5C%20cm%5E2)
Solution,
Since, ΔABC and ΔDEF is similar and ∠B ≅ ∠E.
Therefore,
![\frac{Area\ of\ triangle\ 1}{Area\ of\ triangle\ 2} =\frac{AB^2}{DE^2}](https://tex.z-dn.net/?f=%5Cfrac%7BArea%5C%20of%5C%20triangle%5C%201%7D%7BArea%5C%20of%5C%20triangle%5C%202%7D%20%3D%5Cfrac%7BAB%5E2%7D%7BDE%5E2%7D)
Where triangle 1 and triangle 2 is ΔABC and ΔDEF respectively.
If two triangles are similar, then the ratio of the area of both triangles is proportional to the square of the ratio of their corresponding sides.
![\frac{5}{Area\ of\ triangle\ 2} =\frac{2^2}{6^2}\\ \frac{5}{Area\ of\ triangle\ 2}=\frac{4}{36}\\ Area\ of\ triangle\ 2=\frac{5\times36}{4} =5\times9=45\ cm^2](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7BArea%5C%20of%5C%20triangle%5C%202%7D%20%3D%5Cfrac%7B2%5E2%7D%7B6%5E2%7D%5C%5C%20%5Cfrac%7B5%7D%7BArea%5C%20of%5C%20triangle%5C%202%7D%3D%5Cfrac%7B4%7D%7B36%7D%5C%5C%20Area%5C%20of%5C%20triangle%5C%202%3D%5Cfrac%7B5%5Ctimes36%7D%7B4%7D%20%3D5%5Ctimes9%3D45%5C%20cm%5E2)
Thus the area of ΔDEF is
.
Answer:
0.36 = 36/100 = 9/25
so the simplest form is 9/25