Question

What pressure, in atm, will be exerted by 8 moles of a gas at 300

Answer 1

Answer:

3.94 atm

Explanation:

Using the general gas law equation as follows;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

According to the information provided in this question;

P = ?

V = 50 L

T = 300K

n = 8 mol

Using PV = nRT

P = nRT/V

P = (8 × 0.0821 × 300) ÷ 50

P = 197.04 ÷ 50

P = 3.94 atm