What does ph measure

1 answer:

4 0

PH is a measure of how acidic/basic water is. The range goes from 0 - 14, with 7 being neutral. pHs of less than 7 indicate acidity, whereas a pH of greater than 7 indicates a base. pH is really a measure of the relative amount of free hydrogen and hydroxyl ions in the water.

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In pea plants, purple flowers are dominant to white flowers, and the purple and white alleles are represented with P and p, resp

amm1812

Answer: 75% of the plants are purple and 25% are white. The phenotypic ratio can be expressed as 3:1.

Explanation:

Heterozygous means that its genotype has two distinct alleles, i.e. a dominant and a recessive one. So the genotype of the plants is Pp, and each plant has two alleles since they are diploid organisms, which have two copies of each gene.

Each plant produces gametes, which are haploids cells. That is, they only have one copy of each gene (one allele). So, the gametes produced by Pp have a P or p genotype. During fertilization, the maternal and paternal gamete are fused to form a diploid zygote where their genotype will have one allele from the father and one from the mother.

By making this monohybrid cross, we cross the gametes of each parent in the punnett square (see picture)

In the offspring, we see one PP genotype (homozygous dominant), two Pp genotypes (heterozygous) and one pp genotype (homozygous recessive). Since we know the P allele is dominant and it codes for purple color, a genotype only needs one P allele to express that phenotype. So Pp and PP organisms are purple, and only pp is white. That means 75% of the plants are purple and 25% are white. The phenotypic ratio can be expressed as 3:1.

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Fruit color in a particular plant is controlled by a set of three quantitative trait loci (i.e., QTLs or polygenes), that work i

tankabanditka [31]

Answer:

1/8

Explanation:

Given that the trihybrid parents have AaBbCc genotype for fruit color. The trait is a quantitative trait i.e. each dominant allele will have an additive effect on it. In this case, AaBbCc and AABBCC will not produce same fruit color because AaBbCc has only three loci contributing to the color while in AABBCC all the six loci are contributing to the color. For an offspring to be exactly similar to the AaBbCc parents it should have the same genotype of AaBbCc.

The probability of Aa to come from a cross between Aa and Aa is 2/4 or 1/2

The probability of Bb to come from a cross between Bb and Bb is 2/4 or 1/2

The probability of Cc to come from a cross between Cc and Cc is 2/4 or 1/2

So the collective probability of AaBbCc offspring from a cross between AaBbCc and AaBbCc parents would be=

1/2 * 1/2 * 1/2 = 1/8

Hence, assuming no effects of the environment, 1/8 of the offspring will have the same fruit color phenotype as the trihybrid parent.

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