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Katen [24]
3 years ago
14

How do you graph {x-y=63x+5y=10​

Mathematics
2 answers:
kolbaska11 [484]3 years ago
8 0

Answer: mathaway

Step-by-step explanation:

nasty-shy [4]3 years ago
4 0

Answer:

See below

Step-by-step explanation:

Attached is a graph of the system of equations. Notice that they intersect at the point (5,-1) which is the solution to the system of equations.

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What is the least common multiple of 15 and 6?<br><br> Take notes and show your work.
Mariulka [41]
Hello!

The least common multiple is 3

Hope this helps!
4 0
3 years ago
Q.6. The equation of the ellipse whose centre is at the origin and the x-axis, the major axis, which passes
azamat

<h3>Answer:</h3>

Equation of the ellipse = 3x² + 5y² = 32

<h3>Step-by-step explanation:</h3>

<h2>Given:</h2>

  • The centre of the ellipse is at the origin and the X axis is the major axis

  • It passes through the points (-3, 1) and (2, -2)

<h2>To Find:</h2>

  • The equation of the ellipse

<h2>Solution:</h2>

The equation of an ellipse is given by,

\sf \dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1

Given that the ellipse passes through the point (-3, 1)

Hence,

\sf \dfrac{(-3)^2}{a^2} +\dfrac{1^2}{b^2} =1

Cross multiplying we get,

  • 9b² + a² = 1 ²× a²b²
  • a²b² = 9b² + a²

Multiply by 4 on both sides,

  • 4a²b² = 36b² + 4a²------(1)

Also by given the ellipse passes through the point (2, -2)

Substituting this,

\sf \dfrac{2^2}{a^2} +\dfrac{(-2)^2}{b^2} =1

Cross multiply,

  • 4b² + 4a² = 1 × a²b²
  • a²b² = 4b² + 4a²-------(2)

Subtracting equations 2 and 1,

  • 3a²b² = 32b²
  • 3a² = 32
  • a² = 32/3----(3)

Substituting in 2,

  • 32/3 × b² = 4b² + 4 × 32/3
  • 32/3 b² = 4b² + 128/3
  • 32/3 b² = (12b² + 128)/3
  • 32b² = 12b² + 128
  • 20b² = 128
  • b² = 128/20 = 32/5

Substituting the values in the equation for ellipse,

\sf \dfrac{x^2}{32/3} +\dfrac{y^2}{32/5} =1

\sf \dfrac{3x^2}{32} +\dfrac{5y^2}{32} =1

Multiplying whole equation by 32 we get,

3x² + 5y² = 32

<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>
8 0
3 years ago
There are 72 students in the marching band. The ratio of girls to boys is 19 to 17.
8090 [49]

Answer:

34 boys

Step-by-step explanation:

72 students

G-19:B-17 Ratio

19 + 17 = 36

72/36 = 2

19 x 2 = 38

38 girls

17 x 2 = 34

34 boys

4 0
2 years ago
Can someone help me with a problem?
Kobotan [32]

Answer:

D

Step-by-step explanation:

5 0
3 years ago
1) h(x)=3x3<br>g(x)= - 4x+1<br>Find (h+g)(10)​
Aleksandr-060686 [28]

Answer:

(h+g)(10) = 2691

Step-by-step explanation:

h(x) = 3x^3\\g(x) = -4x+1

Adding both equations will make it:

(h+g)(x) = 3x^3-4x+1

Putting x = 10 will make it:

(h+g)(10) = 3(10)^3-4(10)+1

= 3(1000)-40+1

= 3000-39

= 2961

3 0
3 years ago
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