Answer:
exactly one, 0's, triangular matrix, product and 1.
Step-by-step explanation:
So, let us first fill in the gap in the question below. Note that the capitalized words are the words to be filled in the gap and the ones in brackets too.
"An elementary ntimesn scaling matrix with k on the diagonal is the same as the ntimesn identity matrix with EXACTLY ONE of the (0's) replaced with some number k. This means it is TRIANGULAR MATRIX, and so its determinant is the PRODUCT of its diagonal entries. Thus, the determinant of an elementary scaling matrix with k on the diagonal is (1).
Here, one of the zeros in the identity matrix will surely be replaced by one. That is to say, the determinants = 1 × 1 × 1 => 1. Thus, it is a a triangular matrix.
4(10+3)
40+12
52
Mark brainliest please
Hope this helps you
Spacing needs to be more clear instead of having a giant paragraph. you do not write math in giant paragraphs do you
60% bc i just know these things
Hey There!
Vertical line graphs never represent a function.
Due to this rule, we could eliminate all of the answer choices as it is suggesting the graph is a function.
The only choice which does not suggest the graph is a function is D, is D, if we look further into the answer choice we also see that it displays correct information.
Therefore, the correct answer would only be D.
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