Answer: 6×10-4
Step-by-step explanation:
Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the
10
. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.
6×10-4
Step-by-step explanation:
![1)\ \dfrac{10}{100}=0.10=0.1\\\\2)\ \dfrac{5}{10}=0.5\\\\3)\ \dfrac{6}{10}=0.6\\\\4)\ \dfrac{93}{100}=0.93\\\\5)\ \dfrac{1}{10}=0.1\\\\6)\ \dfrac{40}{100}=0.40=0.4\\\\7)\ \dfrac{56}{100}=0.56\\\\8)\ \dfrac{7}{10}=0.7\\\\9)\ \dfrac{3}{10}=0.3\\\\10)\ \dfrac{98}{100}=0.98\\\\11)\ \dfrac{4}{10}=0.4\\\\12)\ \dfrac{78}{100}=0.78](https://tex.z-dn.net/?f=1%29%5C%20%5Cdfrac%7B10%7D%7B100%7D%3D0.10%3D0.1%5C%5C%5C%5C2%29%5C%20%5Cdfrac%7B5%7D%7B10%7D%3D0.5%5C%5C%5C%5C3%29%5C%20%5Cdfrac%7B6%7D%7B10%7D%3D0.6%5C%5C%5C%5C4%29%5C%20%5Cdfrac%7B93%7D%7B100%7D%3D0.93%5C%5C%5C%5C5%29%5C%20%5Cdfrac%7B1%7D%7B10%7D%3D0.1%5C%5C%5C%5C6%29%5C%20%5Cdfrac%7B40%7D%7B100%7D%3D0.40%3D0.4%5C%5C%5C%5C7%29%5C%20%5Cdfrac%7B56%7D%7B100%7D%3D0.56%5C%5C%5C%5C8%29%5C%20%5Cdfrac%7B7%7D%7B10%7D%3D0.7%5C%5C%5C%5C9%29%5C%20%5Cdfrac%7B3%7D%7B10%7D%3D0.3%5C%5C%5C%5C10%29%5C%20%5Cdfrac%7B98%7D%7B100%7D%3D0.98%5C%5C%5C%5C11%29%5C%20%5Cdfrac%7B4%7D%7B10%7D%3D0.4%5C%5C%5C%5C12%29%5C%20%5Cdfrac%7B78%7D%7B100%7D%3D0.78)
Answer:
The scale factor of a dilation from ABCD to RSTU is ![\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D)
Step-by-step explanation:
We know that the rectangle ABCD is similar to rectangle RSTU.
Given that in rectangle ABCD the longest sides are DC and AB and in the rectangle RSTU the longest sides are UT and RS ⇒ The scale factor of a dilation will transform the sides DC and AB into UT and RS
Working with the lengths of the sides :
DC.(Scale factor) = UT
AB.(Scale factor) = RS
Replacing with the values of the lengths (Scale factor : SF) :
![DC.SF=UT\\(90ft).(SF)=45ft\\SF=\frac{45ft}{90ft} \\SF=\frac{1}{2}](https://tex.z-dn.net/?f=DC.SF%3DUT%5C%5C%2890ft%29.%28SF%29%3D45ft%5C%5CSF%3D%5Cfrac%7B45ft%7D%7B90ft%7D%20%5C%5CSF%3D%5Cfrac%7B1%7D%7B2%7D)
![AB.SF=RS\\(90ft).(SF)=45ft\\SF=\frac{45ft}{90ft} \\SF=\frac{1}{2}](https://tex.z-dn.net/?f=AB.SF%3DRS%5C%5C%2890ft%29.%28SF%29%3D45ft%5C%5CSF%3D%5Cfrac%7B45ft%7D%7B90ft%7D%20%5C%5CSF%3D%5Cfrac%7B1%7D%7B2%7D)
Notice that the scale factor is dimensionless.
We can verify this result with the sides AD and BC :
![AD.SF=UR\\50ft.(\frac{1}{2})=25ft\\ 25ft=25ft](https://tex.z-dn.net/?f=AD.SF%3DUR%5C%5C50ft.%28%5Cfrac%7B1%7D%7B2%7D%29%3D25ft%5C%5C%2025ft%3D25ft)
![BC.SF=TS\\50ft.(\frac{1}{2})=25ft\\ 25ft=25ft](https://tex.z-dn.net/?f=BC.SF%3DTS%5C%5C50ft.%28%5Cfrac%7B1%7D%7B2%7D%29%3D25ft%5C%5C%2025ft%3D25ft)
The scale factor (SF) is ![\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D)
No. Because 5 and 8 do not share a common factor in which they can both simplify.
The results, t (22) = 1.08, p > 0.05, specify that the null hypothesis is plausible. In addition, it is a classification of hypothesis in statistics that puts forward no statistical significance occurs in group of specified interpretations. The null hypothesis tries to display that no variation occurs among variables or that a single variable is no dissimilar than its mean. It is supposed to be true up until statistical evidence nullifies it for an substitute hypothesis. The statistical significance defines that a result from testing or investigating is not likely to happen randomly or by coincidental but is as a substitute likely to be attributable to a precise reason.