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Svetllana [295]
2 years ago
10

Plz help me well mark brainliest if correct

Chemistry
2 answers:
Scrat [10]2 years ago
7 0

Answer:

D) biodiversity

Explanation:

the answer is D) biodiversity

Akimi4 [234]2 years ago
3 0
The correct answer is letter d biodiversity
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What pattern do we see when looking at the fossil record? *
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Answer:

Organisms become more complex over time.

Explanation:

We all evolved from the first bacteria, which was relatively simple. We see over time that things become more adapted, slowly adding eyes, lungs, behavioral patterns, and consciousness.

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An alpha particle is equivalent to a _____ nucleus.
astra-53 [7]
Alpha particle is equivalent to B. Helium atom (2 protons, 2 neutrons) 
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Which nitrogenous base is NOT found in DNA? *
scoundrel [369]

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c. uracil

Explanation:

uracil is not found in DNA. the missing base would be thymine

5 0
3 years ago
What information is need to calculate the percent composition of a compound?
Anestetic [448]

Answer:

Molecular formula

Explanation:

Molecular formula in the first place is required to understand which compound we have. We then should refer to the periodic table and find the molecular weight for each atom. Adding individual molecular weights together would yield the molar mass of a compound.

Then, dividing the total molar mass of a specific atom by the molar mass of a compound and converting into percentage will provide us with the percentage of that specific atom.

E. g., calculate the percent composition of water:

  • molecular formula is H_2O;
  • calculate its molar mass: [tex]M = 2M_H + M_O = 2\cdot 1.00784 g/mol + 16.00 g/mol = 18.016 g/mol;
  • find the percentage of hydrogen: [tex]\omega_H = \frac{2\cdot 1.00784 g/mol}{18.016 g/mol}\cdot 100 \% = 11.19 %;
  • find the percentage of oxygen: [tex]\omega_O = \frac{16.00 g/mol}{18.016 g/mol}\cdot 100 \% = 88.81 %.
8 0
3 years ago
Carbon dioxide (CO2) is a gas at room temperature and pressure. However, carbon dioxide can be put under pressure to become a "s
Lunna [17]

Answer:

The mass of this 25 mL supercritical CO2 sample has a mass of 11.7g

Explanation:

Step 1: Given data

The supercritical CO2 has a density of 0.469 g/cm³ (or 0.469 g/mL)

The sample hasa volume of 25.0 mL

Step 2: Calculating mass of the sample

The density is the mass per amount of volume

0.469g/cm³ = 0.469g/ml

The mass for a sample of 25.0 mL = 0.469g/mL * 25.0 mL = 11.725g ≈ 11.7g

The mass of this 25 mL supercritical CO2 sample has a mass of 11.7g

5 0
3 years ago
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