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Marat540 [252]
3 years ago
7

M-8=33 can you plz help me do this ​

Mathematics
2 answers:
Lyrx [107]3 years ago
6 0

Answer:

M = 41

Step-by-step explanation:

This question is a basic one. Don't let the letter freak you out haha. All you need to do for something like this is find out what minus 8 is 33. An easy way we can do this is just add 8 to 33. 33 + 8 = 41.

41 - 8 = 33.

Your answer is 41.

Hope this helps and have a nice day!

Molodets [167]3 years ago
3 0

Answer:

41

Step-by-step explanation:

m-8=33

Combine like terms by moving 8 to the other side

m=33+8

m=41

I hope this helps! Please comment if you have any questions.

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We have n = 100 many random variables Xi ’s, where the Xi ’s are independent and identically distributed Bernoulli random variab
777dan777 [17]

Answer:

(a) The distribution of X=\sum\limits^{n}_{i=1}{X_{i}} is a Binomial distribution.

(b) The sampling distribution of the sample mean will be approximately normal.

(c) The value of P(\bar X>0.50) is 0.50.

Step-by-step explanation:

It is provided that random variables X_{i} are independent and identically distributed Bernoulli random variables with <em>p</em> = 0.50.

The random sample selected is of size, <em>n</em> = 100.

(a)

Theorem:

Let X_{1},\ X_{2},\ X_{3},...\ X_{n} be independent Bernoulli random variables, each with parameter <em>p</em>, then the sum of of thee random variables, X=X_{1}+X_{2}+X_{3}...+X_{n} is a Binomial random variable with parameter <em>n</em> and <em>p</em>.

Thus, the distribution of X=\sum\limits^{n}_{i=1}{X_{i}} is a Binomial distribution.

(b)

According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.  

The sample size is large, i.e. <em>n</em> = 100 > 30.

So, the sampling distribution of the sample mean will be approximately normal.

The mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu=p=0.50

And the standard deviation of the distribution of sample mean is given by,

\sigma_{\bar x}=\sqrt{\frac{\sigma^{2}}{n}}=\sqrt{\frac{p(1-p)}{n}}=0.05

(c)

Compute the value of P(\bar X>0.50) as follows:

P(\bar X>0.50)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{0.50-0.50}{0.05})\\

                    =P(Z>0)\\=1-P(Z

*Use a <em>z</em>-table.

Thus, the value of P(\bar X>0.50) is 0.50.

8 0
3 years ago
There are 2 mixtures of light purple paint.
solong [7]

Answer:

a

Step-by-step explanation:

7 0
3 years ago
2/3* (1/3+3 1/4 help pls now
ale4655 [162]

Answer:

43/18

Step-by-step explanation:

2/3(1/3+ 3 1/4)

  • First solve parenthesis.

2/3(1/3+ 3 1/4)

find the lowest common denominator (12) to add the two fractions.

1/3= 4/12;  

3 1/4= 13/4 = 39/12

4/12+ 39/12= 43/12

2/3(43/12)

  • Then multiply the fractions.

2/3(43/12)

Numerator: 2*43= 86

Denominator: 3*12= 36

86/36

  • Last simplify your fraction.

43/18 or 2 7/18

4 0
3 years ago
If f(x)= x and g(x) = x - 4 which translation is applied to f(x) to get g(x)
Dafna1 [17]
F(g(x)) = f(x-4) = (x-4)
g(f(x)) = g(x) = x-4
3 0
3 years ago
What is the resulting equation when the expression for y in the second equation is substituted into the first equation-3x+2y=-3
Alex

Answer:

x=-5/11, y=-9/11. (-5/11, -9/11).

Step-by-step explanation:

3x+2y=-3

y=4x+1

---------------

3x+2(4x+1)=-3

3x+8x+2=-3

11x=-3-2

11x=-5

x=-5/11

y=4(-5/11)+1

y=-20/11+11/11

y=-9/11

5 0
2 years ago
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