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Sauron [17]
2 years ago
9

A study was conducted to determine the mean birth weight of a certain breed of kittens. Consider the birth weights of kittens to

be normally distributed. A sample of 45 kittens was randomly selected from all kittens of this breed at a large veterinary hospital. The birth weight of each kitten in the sample was recorded. The sample mean was 3.56 ounces, and the sample standard deviation was 0.2 ounces. Set a 90% confidence interval on the mean birth weight of all kittens of this breed
Mathematics
1 answer:
kipiarov [429]2 years ago
7 0
3.56 +/- 0.011 = ( 3.549, 3.571). This is the answer.
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Step-by-step explanation:

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8 0
2 years ago
An educational psychologist wishes to know the mean number of words a third grader can read per minute.
Rama09 [41]

Answer: 208.

Step-by-step explanation:

The formula to find the minimum sample size is given by :-

n= (\dfrac{z^*\times \sigma}{E})^2                                    (1)

, where z* = critical z-value (two tailed).                                                                      

\sigma = Standard deviation ( from prior study ) and E = Margin of error.

As per given , we have

Margin of error : E= 0.29

Confidence level = 85%

Significance level =\alpha=1-0.85=0.15

Using z-table , the critical value (two -tailed)=z^*=z_{\alpha/2}=z_{0.15/2}=z_{0.075}=1.439

As per previous study , Variance =\sigma^2=8.41

\sigma=\sqrt{8.41}=2.9

Now, the required minimum sample size = n= (\dfrac{(1.439)\times (2.9)}{0.29})^2   [Substitute the values in formula (1)]

n=(14.39)^2

n=207.0721\approx208  [ Round to the next integer]

Hence, the minimum number of third graders that must be included in a sample = 208.

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3 years ago
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