If Keith is represented by x, and Joe is three less than Keith, Troy is represented by x-3.
Then, we know that Joe exercises for twice the amount of time as Troy, we multiply the expression for Joe by two.
Keith = x
Troy = x-3
Joe = 2(x-3)
Answer:
(a) AH < HC is No
(b) AH < AC is Yes
(c) △AHC ≅ △AHB is Yes
Step-by-step explanation:
Given
See attachment for triangle
Solving (a): AH < HC
Line AH divides the triangle into two equal right-angled triangles which are: ABH and ACH (both right-angled at H).
To get the lengths of AH and HC, we need to first determine the measure of angles HAC and ACH. The largest of those angles will determine the longest of AH and HC. Since the measure of the angles are unknown, then we can not say for sure that AH < HC because the possible relationship between both lines are: AH < HC, AH = HC and AH > HC
Hence: AH < HC is No
Solving (b): AH < AC
Length AC represents the hypotenuse of triangle ACH, hence it is the longest length of ACH.
This means that:
AH < AC is Yes
Solving (c): △AHC ≅ △AHB
This has been addresed in (a);
Hence:
△AHC ≅ △AHB is Yes
The answer
by using fundamental definition
<span>The conditional probability of event B given event A is P(B|A)=P(A and B)/P(A) when two events are not independent.
so the only true answer is A, because </span>P(B|A)=P(A) if A and B are independents<span>
(definition)</span>
Answer:
n = 6
Step-by-step explanation:
Two intersecting chords. The product of the parts of one chord is equal to the product of the parts of the other chord, that is
7(n + 4) = 5(n + 8) ← distribute parenthesis on both sides
7n + 28 = 5n + 40 ( subtract 5n from both sides )
2n + 28 = 40 ( subtract 28 from both sides )
2n = 12 ( divide both sides by 2 )
n = 6
Answer:

Step-by-step explanation:
Consider an element 
We know that 
Here, m and n are exponents and a is a base. Exponent refers to the no. of times a term is multiplied by itself. Another word for exponents is powers.
Other Properties of exponents:

Here, we are required to divide
by
.
Consider 
We will solve
separately.
Here,

So, 