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Yanka [14]
3 years ago
11

What is the next number in the sequence? 4488; 44,088; 440,088; 4,400,088

Mathematics
2 answers:
AfilCa [17]3 years ago
8 0

44,00,088 that is ur answer

Nady [450]3 years ago
4 0

the next number would be 44,000,088

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Here is some data showing the age and value of 12 cars.
Bingel [31]

Answer:

Step-by-step explanation:

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The Fun Guys game rental store charges an annual fee of $20 plus $6.50 per game rented. The Game Bank charges an annual fee of $
Sladkaya [172]
<span>In order to find the breakeven number of game rentals, we need to find the point at which the costs are equal. To do this, we set two expressions as a function of the number of games, equate them, and solve.
   For Fun Guys, cost C = 20 + 6.5g, where g is the number of games
 For Game Bank, C = 50 + 3.5g
Equating -> 20 + 6.5g = 50 + 3.5g -> 3g = 30 -> g = 10
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7 0
3 years ago
15x - 10 = -9x + 2 <br> please help me !!!!!
DerKrebs [107]
15x - 10 = -9x + 2

15x +9x -10 = -9x + 9x + 2

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15 x + 9 x = 2 + 10

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6 0
3 years ago
......ssssssssssssssssssssssssssssssssssssshhhhhh
Darina [25.2K]

Hey there! I'm happy to help!

Step 2 is incorrect. She added 4 and 2 first, but you are supposed to multiply and divide first. Then she multiplied 6 and 6, which is 36. Then she divided 36 and 2, which is 18, and then she subtracted 7, giving her 11. Step 2 is what threw the whole thing off.

Here is what Sandy should have done.

STEP 1: 6·4+2÷2-7

STEP 2: 24+1-7

STEP 3: 25-7

STEP 4: 18

I hope that this helps! Have a wonderful day! :D

3 0
3 years ago
Read 2 more answers
The value of a certain car decreases by 16% each year. What is the 1⁄2-life of the car?
svet-max [94.6K]

Answer:

The half life of the car is 3.98 years.

Step-by-step explanation:

The value of the car after t years is given by the following equation:

V(t) = V(0)(1-r)^{t}

In which V(0) is the initial value and r is the constant decay rate, as a decimal.

The value of a certain car decreases by 16% each year.

This means that r = 0.16

So

V(t) = V(0)(1-r)^{t}

V(t) = V(0)(1-0.16)^{t}

V(t) = V(0)(0.84)^{t}

What is the 1⁄2-life of the car?

This is t for which V(t) = 0.5V(0). So

V(t) = V(0)(0.84)^{t}

0.5V(0) = V(0)(0.84)^{t}

(0.84)^{t} = 0.5

\log{(0.84)^{t}} = \log{0.5}

t\log{0.84} = \log{0.5}

t = \frac{\log{0.5}}{\log{0.84}}

t = 3.98

The half life of the car is 3.98 years.

7 0
3 years ago
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