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Angelina_Jolie [31]
4 years ago
11

Will mark brainliest and 50 points. What is (2^8x5^-5x19^0)^-2x(5^-2/2^3)^4x2^28 show your work.

Mathematics
1 answer:
Kaylis [27]4 years ago
8 0

Answer:

im quite confused with the way its been layed out

cant tell if ur multiplying of its a X

Step-by-step explanation:

(2^8 times 5 ^-8 times 1) ^-2x times 5^-2 over 2^3 times 4 times 2 ^28

(2^-16x times 5^10x times 5^-2 over 8 times 4 times 2^28

2^16=28 times 5 ^10x

------------------------------- over

50

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Bassima evaluated the expression below.
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Add 6 to the quotient of j and k
BARSIC [14]

Answer:

     j/k + 6

Step-by-step explanation:

Add 6 to the quotient of j and k comes out to:

                                  j/k + 6

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The sum of two consecutive terms in the arithmetic sequence 3​, 6​, 9​, 12​, ... is 303​; find these two terms.
Nikolay [14]
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3 0
3 years ago
Consider random samples of size 58 drawn from population A with proportion 0.77 and random samples of size 70 drawn from populat
fredd [130]

Answer:

Step-by-step explanation:

a) The formula for determining the standard error of the distribution of differences in sample proportions is expressed as

Standard error = √{(p1 - p2)/[(p1(1 - p1)/n1) + p2(1 - p2)/n2}

where

p1 = sample proportion of population 1

p2 = sample proportion of population 2

n1 = number of samples in population 1,

n2 = number of samples in population 2,

From the information given

p1 = 0.77

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p2 = 0.67

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= √1/0.0063

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the standard error of the distribution of differences in sample proportions is 12.6

b) the sample sizes are large enough for the Central Limit Theorem to apply because it is greater than 30

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