Answer:
The time interval when
is at 
The distance is 106.109 m
Step-by-step explanation:
The velocity of the second particle Q moving along the x-axis is :

So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.
We are also to that :
between 
The schematic free body graphical representation of the above illustration was attached in the file below and the point when
is at 4 is obtained in the parabolic curve.
So,
is at 
Taking the integral of the time interval in order to determine the distance; we have:
distance = 
= 
= By using the Scientific calculator notation;
distance = 106.109 m
Answer:
Ok, the solution to the first one. See below.
Step-by-step explanation:

See attachment below.
Best Regards!
I'm not sure but I think it is
4.48×10 10 <---this to is an exponent
Answer:
2
Step-by-step explanation:
Since if it's 5 or higher you go up but if it's 4 or lower you stay the same. And since 2.36 doesn't have the .5 it would round to 2
Answer:
Step-by-step explanation:
3x+6=-5-2x-6
+2x. +2x
5x+6= -5-6
5x+6= -11
-6. -6
5x= -17
divide by 5
x= -3.4