Answer:
we have to put the numbers in order..
(121,122,125, 126,132),M,(135,136,136,138,140)
Step-by-step explanation:
minimum : (smallest number) = 121
Q1 : 125
Q2 (median) : (132 + 135) / 2 = 267/2 = 133.5
Q3 : 136
maximum : (largest number) = 140
I did this a long time ago so im not so sure
<h2>○=> <u>Correct option</u> :</h2><h2>

</h2><h3>○=> <u>Steps to derive correct option</u> :</h3>
We know that :

So, let the diameter of this circle be x.
Which means :





Thus, the radius of the circle Robert drew = 6 m
Since the circle in option B has a radius of 6 m, it is the circle Robert drew.
▪︎<em>Therefore, the correct option is (B)</em>
Answer:
The answer is $7.15 (A)
Step-by-step explanation:
Answer:

Step-by-step explanation:

Using rule of exponents 

Using rule of exponents 


To equalize the negative sign, we'll move t to the denominator
