Might have to experiment a bit to choose the right answer.
In A, the first term is 456 and the common difference is 10. Each time we have a new term, the next one is the same except that 10 is added.
Suppose n were 1000. Then we'd have 456 + (1000)(10) = 10456
In B, the first term is 5 and the common ratio is 3. From 5 we get 15 by mult. 5 by 3. Similarly, from 135 we get 405 by mult. 135 by 3. This is a geom. series with first term 5 and common ratio 3. a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.
Can you now examine C and D in the same manner, and then choose the greatest final value? Safe to continue using n = 1000.
Answer:
2400
Step-by-step explanation:
x+y+z=147
x+(x+1)+(x+2)=147
3x+3=147
3x=144
x=48
The three consecutive positive numbers are 48, 49, and 50.
48 • 50 = 2400
Answer:
100%
Step-by-step explanation:
100% of the shelters received 1,000 or fewer cans per month since all the data values in the box and whisker plot are below 1,000 indicating that homeless shelter received more than 1,000 cans.
# of apples
3/8(a)=# of oranges
p=# of pears
3/4(p)=# of oranges
(3/8)a=(3/4)p
(3/8)/(3/4)=p/a
(3/8)(6/8)=p/a
3/6=p/a
1/2=p/a
the ratios of pears to apples is 1 to 2
for every 1 pear there are 2 apples
if there are 4 pears there are 8 apples
there are 8 apples
(3/8)(8)=3 oranges
there are 4 pears
(3/4)(4)=3 oranges again
8 apples, 3 oranges, 4 pears
15 pieces of fruit and 3 are oranges
ratio is 3/15=1/5
4/5/2015 | Arthur D.
Answer:
1
Step-by-step explanation:
The number 1 stands for 1 thousand, and all the other numbers stand for a smaller value.
