Answer:
The value of SecФ is 
.
Step-by-step explanation:
Given as for trigonometric function :
tan²Ф = 
Or, tanФ = 
∵ tanФ = 
So, =
So, Hypotenuse² = perpendicular² + base²
or, Hypotenuse² = ( 
)² + ( 
)²
Or, Hypotenuse² = 3 + 8 = 11
Or, Hypotenuse = ( 
)
Now SecФ = 
or, SecФ = 
= 
<u>Second Method</u>
Sec²Ф - tan²Ф = 1
Or, Sec²Ф = 1 + tan²Ф
or, Sec²Ф = 1 +
Or, Sec²Ф = 
Or, SecФ =
Hence The value of SecФ is . Answer
Step-by-step explanation:
Hey there!
The equation of a line which passes through the point (1,1) is <em>(y-1) = m1 (x-1)...............(i)</em> {using one point formula}
Also, another equation which is perpendicular to the line is <em>y = 1/5 x + 4/5..........(ii)</em>
Comparing equation (ii) with y= mx+c, we get;
Slope (m2) = 1/5.
Now, As per the condition of perpendicular lines,
m1*m2 = -1
or, m1 * 1/2 = -1
or, m1= -2
Therefore, m1 = -2.
Keeping the value of m1 in equation (i) we get;
y-1 = -2(x-1)
y-1 = -2x+1
or, y+2x-2= 0
Therefore, the required equation is 2x+y-2= 0.
Hope it helps!
Divide the MAD of the 6th graders by the MAD of the 7th graders:
1.2 / 1.0 = 1.2
The answer is 1.2
Step-by-step explanation:
x. y=3x². y=3^x
0. 0. 1
1. <u>3</u><u> </u> <u>3</u><u> </u>
2. <u>12</u><u>. </u> <u>9</u><u>.</u>
hope this helps you. Just put the value of x in the equations of y.
The probability that he selected the special quarter is 87.5%.
<h3><u /></h3><h3><u>Probability</u></h3>
Given that Mandvil has one standard quarter and one special quarter with a Head on both sides, and he selects one of these two coins at random, and without looking at it first, he flips the coin three times, to determine, if he flips a Head three straight times, what is the probability that he selected the special quarter, the following calculation must be made:
- 1 - (standard quarter) = X
- 1 - (0.50^3) = X
- 1 - 0.125 = X
- 0.875 = X
- 0.875 x 100 = 87.5
Therefore, the probability that he selected the special quarter is 87.5%.
Learn more about probability in brainly.com/question/24217562
